c++ - 应用程序无法使用 CreateWindowStation 创建 Windows 站

Question

我无法创建新的 Window Station 来运行我的应用程序

int _tmain(int argc, TCHAR* argv[], TCHAR* envp[])
{
    wprintf(L"SetProcessWindowStation() before: %x\n", GetProcessWindowStation());
    HWINSTA winSta = CreateWindowStation(_T("hiddenWinSta"), 0, 0, NULL);
     if (winSta == NULL)
     {
        wprintf(L"CreateWindowStation() failed, error %d!\n", GetLastError());
     }else
        wprintf(L"CreateWindowStation() is OK!\n");
    SetProcessWindowStation(winSta);
    OpenDesktop(L"default", 0, FALSE, READ_CONTROL | WRITE_DAC | DESKTOP_WRITEOBJECTS | DESKTOP_READOBJECTS);
    wprintf(L"SetProcessWindowStation() after: %x\n", GetProcessWindowStation());
    system("pause");
    return 0;
}

我可以为新的 windows station 截屏吗？winsta0 和 desktop default 不是吗？请帮助我:(

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输出

SetProcessWindowStation() before: 30
CreateWindowStation() failed, error 5!
SetProcessWindowStation() after: 30
Press any key to continue . . .

Answer 1

错误 5 是 ERROR_ACCESS_DENIED

来自 CreateWindowStation

lpwinsta [in, optional]

The name of the window station to be created. Window station names are case-insensitive and cannot contain backslash characters \. Only members of the Administrators group are allowed to specify a name. If lpwinsta is NULL or an empty string, the system forms a window station name using the logon session identifier for the calling process. To get this name, call the GetUserObjectInformation function.

因此，要么以管理员身份启动程序，要么不指定名称。