java - EC2 Windows - 获取管理员密码

Question

目前，我知道从新创建的 EC2 Windows 实例中检索管理员密码的唯一方法是通过 AWS 管理控制台。这很好，但我需要知道如何通过 Java API 完成此操作——我似乎无法找到有关该主题的任何内容。另外，获得密码后，如何使用相同的 API 修改密码？

Answer 1

EC2 API 有一个调用“GetPasswordData”，您可以使用它来检索包含管理员密码的加密数据 block 。要解密它，您需要两件事:

首先是私钥。这是您用来实例化实例的 key 对的私有(private)部分。一个复杂的问题是，亚马逊通常使用 PEM 格式的 key (“-----BEGIN”...)，但 Java Crypto API 需要 DER 格式的 key 。您可以自己进行转换 - 去掉 -----BEGIN 和 -----END 行，取出中间的文本 block 并对其进行 base64 解码。

二、加密参数。数据是用 RSA 加密的，用 PKCS1 填充——所以给 JCE 的魔法调用是:Cipher.getInstance("RSA/NONE/PKCS1Padding")

这是一个完整的示例(依赖于 BouncyCaSTLe，但可以修改为使用不同的加密引擎)

package uk.co.frontiertown;

import com.amazonaws.auth.AWSCredentials;
import com.amazonaws.auth.BasicAWSCredentials;
import com.amazonaws.services.ec2.AmazonEC2Client;
import com.amazonaws.services.ec2.model.GetPasswordDataRequest;
import com.amazonaws.services.ec2.model.GetPasswordDataResult;
import org.bouncycastle.jce.provider.BouncyCastleProvider;
import org.bouncycastle.util.encoders.Base64;

import javax.crypto.Cipher;
import java.nio.charset.Charset;
import java.security.GeneralSecurityException;
import java.security.KeyFactory;
import java.security.PrivateKey;
import java.security.Security;
import java.security.spec.PKCS8EncodedKeySpec;

public class GetEc2WindowsAdministratorPassword {

    private static final String ACCESS_KEY = "xxxxxxxxxxxxxxxxxxxx";
    private static final String SECRET_KEY = "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx";
    private static final String PRIVATE_KEY_MATERIAL = "-----BEGIN RSA PRIVATE KEY-----\n" +
        "MIIEowIBAAKCAQEAjdD54kJ88GxkeRc96EQPL4h8c/7V2Q2QY5VUiJ+EblEdcVnADRa12qkohT4I\n" +
        // several more lines of key data
        "srz+xXTvbjIJ6RL/FDqF8lvWEvb8uSC7GeCMHTznkicwUs0WiFax2AcK3xjgtgQXMgoP\n" +
        "-----END RSA PRIVATE KEY-----\n";

    public static void main(String[] args) throws GeneralSecurityException, InterruptedException {
        Security.addProvider(new BouncyCastleProvider());
        String password = getPassword(ACCESS_KEY, SECRET_KEY, "i-XXXXXXXX", PRIVATE_KEY_MATERIAL);
        System.out.println(password);
    }

    private static String getPassword(String accessKey, String secretKey, String instanceId, String privateKeyMaterial) throws GeneralSecurityException, InterruptedException {

        // Convert the private key in PEM format to DER format, which JCE can understand
        privateKeyMaterial = privateKeyMaterial.replace("-----BEGIN RSA PRIVATE KEY-----\n", "");
        privateKeyMaterial = privateKeyMaterial.replace("-----END RSA PRIVATE KEY-----", "");
        byte[] der = Base64.decode(privateKeyMaterial);
        PKCS8EncodedKeySpec keySpec = new PKCS8EncodedKeySpec(der);
        KeyFactory keyFactory = KeyFactory.getInstance("RSA");
        PrivateKey privateKey = keyFactory.generatePrivate(keySpec);

        // Get the encrypted password data from EC2
        AWSCredentials awsCredentials = new BasicAWSCredentials(accessKey, secretKey);
        AmazonEC2Client client = new AmazonEC2Client(awsCredentials);
        GetPasswordDataRequest getPasswordDataRequest = new GetPasswordDataRequest().withInstanceId(instanceId);
        GetPasswordDataResult getPasswordDataResult = client.getPasswordData(getPasswordDataRequest);
        String passwordData = getPasswordDataResult.getPasswordData();
        while (passwordData == null || passwordData.isEmpty()) {
            System.out.println("No password data - probably not generated yet - waiting and retrying");
            Thread.sleep(10000);
            getPasswordDataResult = client.getPasswordData(getPasswordDataRequest);
            passwordData = getPasswordDataResult.getPasswordData();
        }

        // Decrypt the password
        Cipher cipher = Cipher.getInstance("RSA/NONE/PKCS1Padding");
        cipher.init(Cipher.DECRYPT_MODE, privateKey);
        byte[] cipherText = Base64.decode(passwordData);
        byte[] plainText = cipher.doFinal(cipherText);
        String password = new String(plainText, Charset.forName("ASCII"));

        return password;
    }
}

ObDisclosure:我最初是在 http://www.frontiertown.co.uk/2012/03/java-administrator-password-windows-ec2-instance/ 的博客上回答这个问题的