PHP检查提交了哪个表单

Question

我在一个网站上工作，我在 1 个页面上有 2 个表格。我使用 1 个 PHP 脚本来检查表格。但是如果我在页面上提交我的第二个表单，我的网站会提交第一个表单。我如何检查提交了哪个表单？

<!--// Form 1-->
<form method="post">

<input type="text" name="test">
<input type="submit" name="submit">
<input type="hidden" name="page_form" value="1">

</form>

<!--// Form 2-->
<form method="post">

<input type="text" name="test">
<input type="submit" name="submit">
<input type="hidden" name="page_form" value="2">

</form>

PHP:

if(isset($_POST['submit'])) {

    $forms = array(1, 2);
    foreach($forms as $form) {

        if($_POST['page_form'] == $form) {
        // All my form validations which are for every form the same.

        }       
    }            
}    

Answer 1

这样做的方法:

<!--// Form 1-->
<form method="post">

<input type="text" name="test">
<input type="submit" name="form1" value="Submit form">

</form>

<!--// Form 2-->
<form method="post">

<input type="text" name="test">
<input type="submit" name="form2" value="Submit form">

</form>

并检查提交了哪个表单:

if(isset($_POST["form1"]))
   echo "Form 1 have been submitted";
else if(isset($_POST["form2"]))
   echo "Form 2 have been submitted";