c# - 在另一个用户的凭据下启动进程

Question

我想在另一个用户名的凭据下启动一个进程。这就是我现在拥有的:

        /// <summary>
        /// Do actions under another username's credentials
        /// </summary>
        /// <param name="username">Username to inpersonate</param>
        /// <param name="domain">Domain/Machine</param>
        /// <param name="password">Password </param>
        public static void Action(string username,string domain, string password )
        {
            try
            {
                if (LogonUser(username, domain, password, LOGON32_LOGON_INTERACTIVE, LOGON32_PROVIDER_DEFAULT, ref hToken))
                {
                    if (DuplicateToken(hToken, 2, ref hTokenDuplicate))
                    {

                        WindowsIdentity windowsIdentity = new WindowsIdentity(hTokenDuplicate);

                        WindowsImpersonationContext impersonationContext = windowsIdentity.Impersonate();

                        // Check the identity but it could do any other action under given username credentials
                      try
                        {
                            ProcessStartInfo info = new ProcessStartInfo("cmd.exe");
                            info.UseShellExecute = false;
                            info.RedirectStandardInput = true;
                            info.RedirectStandardError = true;
                            info.RedirectStandardOutput = true;
                            info.UserName = "dummy"; // see the link mentioned at the top
                            // Define the string value to assign to a new secure string.
                            char[] chars = { 'p', 'a', 's', 's','1','2','3','4','/' };
                            // Instantiate the secure string.
                            SecureString testString = new SecureString();
                            // Assign the character array to the secure string.
                            foreach (char ch in chars)
                                testString.AppendChar(ch);

                            info.Password = testString;

                            Process.Start(info);

                        }
                        catch (Exception ex)
                        {
                            Console.WriteLine("Exception Occurred :{0},{1}",ex.Message, ex.StackTrace.ToString());
                        }

                        // Stop impersonating the user
                        impersonationContext.Undo();
                    }
                }
                // Free the tokens
                if (hToken != IntPtr.Zero) 
                    CloseHandle(hToken);
                if (hTokenDuplicate != IntPtr.Zero)
                    CloseHandle(hTokenDuplicate);

        }catch(Exception ex)
         {
             Console.WriteLine("Exception occurred. " + ex);
          }

它似乎不起作用，我收到“访问被拒绝”的提示。关于如何做的任何想法？如果我们要求凭据，我们会得到正确的凭据，因此它应该在该凭据下执行任何程序。即:

               if (DuplicateToken(hToken, 2, ref hTokenDuplicate))
                    {

                        WindowsIdentity windowsIdentity = new WindowsIdentity(hTokenDuplicate);                      
                        WindowsImpersonationContext impersonationContext = windowsIdentity.Impersonate();

                        // Check the identity but it could do any other action under given username credentials
                        Console.WriteLine("After impersonation: {0}", WindowsIdentity.GetCurrent().Name);

                        // Stop impersonating the user
                        impersonationContext.Undo();
                    }

答案是正确的，我们得到了“虚拟”。

我们可以让它更简单:

 public static void Run()
        {
            try
            {
                const string file = "cmd.exe";

                var sspw = new SecureString();

                foreach (var c in "pass1234/")
                    sspw.AppendChar(c);

                var proc = new Process();

                proc.StartInfo.UseShellExecute = false;

                proc.StartInfo.WorkingDirectory = Path.GetDirectoryName(file);

                proc.StartInfo.FileName = Path.GetFileName(file);

                proc.StartInfo.Domain = "WIN08";
                proc.StartInfo.Arguments = "";
                proc.StartInfo.UserName = "dummy";
                proc.StartInfo.Password = sspw;
                proc.StartInfo.LoadUserProfile = false;
                proc.Start();
            }catch(Exception e)
            {
                Console.WriteLine(e);
             }

但是，我仍然遇到异常......

Answer 1

对于某些人来说这可能很奇怪，我很抱歉，我是 Linux 开发人员......测试:

    /// <summary>
    /// Class that deals with another username credentials
    /// </summary>
    class Credentials
    {
        /// <summary>
        /// Constructor of SecureString password, to be used by RunAs
        /// </summary>
        /// <param name="text">Plain password</param>
        /// <returns>SecureString password</returns>
        private static SecureString MakeSecureString(string text)
        {
            SecureString secure = new SecureString();
            foreach (char c in text)
            {
                secure.AppendChar(c);
            }

            return secure;
        }

        /// <summary>
        /// Run an application under another user credentials.
        /// Working directory set to C:\Windows\System32
        /// </summary>
        /// <param name="path">Full path to the executable file</param>
        /// <param name="username">Username of desired credentials</param>
        /// <param name="password">Password of desired credentials</param>
        public static void RunAs(string path, string username, string password)
        {
            try
            {
                ProcessStartInfo myProcess = new ProcessStartInfo(path);
                myProcess.UserName = username;
                myProcess.Password = MakeSecureString(password);
                myProcess.WorkingDirectory = @"C:\Windows\System32";
                myProcess.UseShellExecute = false;
                Process.Start(myProcess);
            }
            catch (Win32Exception w32E)
            {
                // The process didn't start.
                Console.WriteLine(w32E);
            }
        }

    }