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javascript - 如何从 AJAX 提交的表单中获取响应?

转载 作者:可可西里 更新时间:2023-11-01 13:46:44 25 4
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我想使用 Acymailing Joomla!安装在 example.com/mailer 的组件,用于管理来自 example.com 上非 Joomla 站点的订阅

在那种情况下我有简单的脚本

 $(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'https://example.com/mailer/index.php?option=com_acymailing&ctrl=sub',
data: $('form').serialize(),
success: function () {
swal('Great success!');
}
});
});
});

和形式

<form class="form-inline" action="https://example.com/mailer/index.php?option=com_acymailing&ctrl=sub" method="post">
<div class="form-group">
<label class="sr-only" for="user_name">Email address</label>
<input id="user_name" type="text" name="user[name]" value="" class="form-control" placeholder="Email">
</div>
<div class="form-group">
<label class="sr-only" for="user_email">Password</label>
<input id="user_email" type="text" name="user[email]" value="" class="form-control" placeholder="Password">
</div>
<button type="submit" class="btn btn-default">Sign Up!</button>
<input type="hidden" name="user[html]" value="1" />
<input type="hidden" name="acyformname" value="formAcymailing1" />
<input type="hidden" name="ctrl" value="sub"/>
<input type="hidden" name="task" value="optin"/>
<input type="hidden" name="redirect" value="https://example.com"/>
<input type="hidden" name="option" value="com_acymailing"/>
<input type="hidden" name="visiblelists" value=""/>
<input type="hidden" name="hiddenlists" value="1"/>
</form>

一切正常,除了成功、错误状态...

Joomla Acymailing 有 sub.php 文件来处理 ajax 响应

 if($config->get('subscription_message',1) || $ajax){
if($allowSubscriptionModifications){
if($statusAdd == 2){
if($userClass->confirmationSentSuccess){
$msg = 'CONFIRMATION_SENT';
$code = 2;
$msgtype = 'success';
}else{
$msg = $userClass->confirmationSentError;
$code = 7;
$msgtype = 'error';
}
}else{
if($insertMessage){
$msg = 'SUBSCRIPTION_OK';
$code = 3;
$msgtype = 'success';
}elseif($updateMessage){

$msg = 'SUBSCRIPTION_UPDATED_OK';
$code = 4;
$msgtype = 'success';
}else{
$msg = 'ALREADY_SUBSCRIBED';
$code = 5;
$msgtype = 'success';
}
}
}else{
if($modifySubscriptionSuccess){
$msg = 'IDENTIFICATION_SENT';
$code = 6;
$msgtype = 'warning';
}else{
$msg = $modifySubscriptionError;
$code = 8;
$msgtype = 'error';
}
}

if($msg == strtoupper($msg)){
$source = acymailing_getVar('cmd', 'acy_source');
if(strpos($source, 'module_') !== false){
$moduleId = '_'.strtoupper($source);
if(acymailing_translation($msg.$moduleId) != $msg.$moduleId) $msg = $msg.$moduleId;
}
$msg = acymailing_translation($msg);
}

$replace = array();
$replace['{list:name}'] = '';
foreach($myuser as $oneProp => $oneVal){
$replace['{user:'.$oneProp.'}'] = $oneVal;
}
$msg = str_replace(array_keys($replace),$replace,$msg);

if($config->get('redirect_tags', 0) == 1) $redirectUrl = str_replace(array_keys($replace),$replace,$redirectUrl);

if($ajax){
$msg = str_replace(array("\n","\r",'"','\\'),array(' ',' ',"'",'\\\\'),$msg);
echo '{"message":"'.$msg.'","type":"'.($msgtype == 'warning' ? 'success' : $msgtype).'","code":"'.$code.'"}';
}elseif(empty($redirectUrl)){
acymailing_enqueueMessage($msg,$msgtype == 'success' ? 'info' : $msgtype);
}else{
if(strlen($msg)>0){
if($msgtype == 'success') acymailing_enqueueMessage($msg);
elseif($msgtype == 'warning') acymailing_enqueueMessage($msg,'notice');
else acymailing_enqueueMessage($msg,'error');
}
}
}

JSON 看起来像在 Joomla 端通过 index.php?option=com_acymailing&ctrl=sub 注册到相同的表单

 message    Subscribe confirmed
type success
code 3

{"message":"Subscribe confirmed","type":"success","code":"3"}

问题是:如何在外部提交表单(在 example.com 页面)上获取提交状态成功、错误、已提交等?

最佳答案

这个简单的更改可能会为您完成:

$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'https://example.com/mailer/index.php?option=com_acymailing&ctrl=sub',
data: $('form').serialize()
}
}).done(function (data) {
swal('Great success!');
});
});
});

我个人喜欢:

$.post("https://example.com...", {
data: $('form').serialize()
}, function(data) {
swal('Great success!');
});

因为您的结果是 JSON,所以应该更像:

$.post("https://example.com...", {
data: $('form').serialize()
}, function(data) {
console.log(data); // shows full return object in console
swal('Great success!');
}, "json");

关于javascript - 如何从 AJAX 提交的表单中获取响应?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47877603/

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