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javascript - ajax的序列化方法不返回所需的值

转载 作者:可可西里 更新时间:2023-11-01 13:41:27 25 4
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我正在尝试通过 ajax j 查询引导模式获取表单输入并将其存储到数据库中,但序列化方法没有返回所有需要的值。

它应该返回 user_id 和 btn_action 的值...我哪里出错了..??

我尝试了很多解决方案,但无法得到任何答案......

下面是 html 和 javascript 代码。我正在使用所有必需的 jquery 资源。

<form method="post" id="user_form">
<div class="modal-content">
<div class="modal-header">
<h4 class="modal-title"></i> Add User
</h4>
<button type="button" class="close" data-dismiss="modal">&times;
</button>

</div>
<div class="modal-body">
<div class="form-group">
<label>Enter User Name</label>
<input type="text" name="user_name" id="user_name" class="form-control" required />
</div>
<div class="form-group">
<label>Enter User Email
</label>
<input type="email" name="user_email" id="user_email" class="form-control" required />
</div>
<div class="form-group">
<label>Enter User Password</label>
<input type="password" name="user_password" id="user_password" class="form-control" required />
</div>
</div>
<div class="modal-footer">
<input type="hidden" name="user_id" id="user_id" />
<input type="hidden" name="btn_action" id="btn_action" />
<input type="submit" name ="action" id= "action" class="btn btn-primary"
value="Add" />
<button type="button" class="btn btn-default" data-dismiss="mo
dal">Close</button>
</div>
</div>
</form>

//script code:

$(document).on('submit', '#user_form', function(event){
event.preventDefault();
$('#action').attr('disabled','disabled');
var form_data = $('#user_form').serialize();
alert(form_data);
// console.log(form_data)
$.ajax({
url:"user_action.php",
method:"POST",
data:form_data,
success:function(data)

{
$('#user_form')[0].reset();
$('#userModal').modal('hide');
$('#alert_action').fadeIn().html('<div class="alert alert-success">'+data+'</div>');
$('#action').attr('disabled', false);## Heading ##

}
});
});

<script>

$(document).on('click','#add_button',function(){
$('#action').val("Insert");

$('.modal-title').text("Add User");

});

$(document).on('submit', '#user_form', function(event){
event.preventDefault();


var form_data = $('#user_form').serialize();
alert(form_data);//not returning the required values

$.ajax({
url:"user_action.php",
method:"POST",
data:form_data,
contentType:false,
processData:false,
success:function(data)

{
$('#user_form')[0].reset();
$('#userModal').modal('hide');
$('#alert_action').fadeIn().html('<div class="alert alert-success">'+data+'</div>');
$('#action').attr('disabled', false);
userdataTable.ajax.reload();
}
});
});





});


</script>
<!-- form -->
<form method="post" id="user_form">
<div class="modal-content">
<div class="modal-header">
<h4 class="modal-title"></i> Add User</h4>
<button type="button" class="close" data-dismiss="modal">&times;</button>

</div>
<div class="modal-body">
<div class="form-group">
<label>Enter User Name</label>
<input type="text" name="user_name" id="user_name" class="form-control" required />
</div>
<div class="form-group">
<label>Enter User Email</label>
<input type="email" name="user_email" id="user_email" class="form-control" required />
</div>
<div class="form-group">
<label>Enter User Password</label>
<input type="password" name="user_password" id="user_password" class="form-control" required />
</div>
</div>
<div class="modal-footer">
<input type="hidden" name="user_id" id="user_id" />
<input type="hidden" name="btn_action" id="btn_action" />
<input type="submit" name ="action" id= "action" class="btn btn-primary" value="Add" />
<button type="button" class="btn btn-default" data-dismiss="mo dal">Close</button>
</div>
</div>
</form>

</div>
</div>

最佳答案

这两个隐藏的输入没有附加值,因此您不会在序列化值中找到它们,直接在 html 中或使用 javascript 向输入添加一些值

 <input type="hidden" name="user_id" id="user_id" value="some user_id"/>
<input type="hidden" name="btn_action" id="btn_action" value="some btn_action"/>

关于javascript - ajax的序列化方法不返回所需的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56785617/

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