php - __get() 函数在 php 中的行为

Question

我试图找到在 PHP 中调用魔法方法的顺序。因此写了一个非常基础的程序

class testme
{
    public $var1;
    /*function __construct()
    {
        echo'<br/> Constructor called';
    }*/
      public function __set($name, $value)
    {
        echo'<br/> You are in sssset function';
    }
    public function __call($method,$arg)
    {
        echo '<br/> call method';
    }
    public function __get($name)
    {
        echo'<br/> You are in get function';
    }
    public function __isset($name)
    {
        echo'<br/> You are in isset function';
    }
    public function __unset($name)
    {
        echo'<br/> You are in unset function';
    }   
       function __destruct() {
       print "<br/>Destroying " . $this->name . "\n";
   }
}
$obj = new testme;
$obj->var1=5;

预期的输出是

You are in set function
Destroying 

获得:

You are in get function
Destroying 

$obj->var1=5 在这里，我将值设置为类 var 然后它调用 __get 的原因。这里有什么问题？

Answer 1

如果您在 __get 中对 $name 执行 var_dump，您会看到它包含 name . __get函数实际上是在__destruct中调用的。这是因为 $var1 是可访问成员，因此不会调用 __get 或 __set 函数。

来自PHP Documentation:

The overloading methods are invoked when interacting with properties or methods that have not been declared or are not visible in the current scope. The rest of this section will use the terms "inaccessible properties" and "inaccessible methods" to refer to this combination of declaration and visibility.

由于 $var1 已定义且公开，因此不会调用魔法方法。