javascript - 弹出框自动关闭

Question

我需要在 3 秒内自动关闭弹出框。

请大家帮帮我

html:

<div align="center">
<!--Validation Dialogue box popup-->
<div id="blanket" style="display:none;"></div>
<div id="validationPopup" style="display:none;">
</br>

<div id="validationMessage" align="center"></div>
</div>

<form id="Reject118" name="Reject118" method="post" action="#" onsubmit="return reject_validation(this.name);">
        <input type="submit" class="Reject" name="Reject" id="Reject" value="Reject" title="Click here to Reject this product item & send back for Moderator's Review" />
        <br />
        <textarea name="reject_reason" id="reject_reason" rows="3" cols="9" onblur="if(this.value == '')
{ this.value = 'Type Reject Reason Here';
this.style.color = '#8f8484';}" onfocus="if(this.value == 'Type Reject Reason Here'){ this.value = ''; this.style.color = '#8f8484';}" style="color:#8f8484;">Type Reject Reason Here</textarea>
</form>

我的 fiddle

FIDDLE

Answer 1

我猜 getElementById 是弹出元素，在这种情况下，下面的 JS 应该可以工作:

setTimeout(function(){
   document.getElementById('validationPopup').style.display='none';
},3000)