php - 比较值顺序不同的两个数组

Question

有没有快速的方法来做这样的事情Compare two arrays with the same value but with a different order在 PHP 中？

我有可能包含相同数据但顺序不同的数组，我只需要查看它们是否相同。

好吧，结果我得到了一个对象而不是一个数组，我猜...

object(Doctrine\ORM\PersistentCollection)#560 (9) etc.

嗯...最简单的方法也许是迭代集合的内容以创建我自己的数组，然后像大家建议的那样进行比较？

只需为我的最终解决方案添加代码

        //Find out if container receives mediasync
        $toSync = array();
        foreach($c->getVideosToSync() as $v) {
            $toSync[] = $v->getId();
        }

        $inSync = array();
        foreach($c->getVideosInSync() as $v) {
            $inSync[] = $v->getId();
        }

        $noDiff = array_diff($toSync, $inSync);
        $sameLength = count($toSync) === count($inSync);

        if( empty($noDiff) && $sameLength ) {
           $containerHelper[$c->getId()]['syncing'] = false;
        }
        else {
            $containerHelper[$c->getId()]['syncing'] = true;    
        }

Answer 1

我是这样解决的:

<?php

$arrayOld=array(
    '1'=>'32',
    '2'=>'34',
    '3'=>'36',
    '4'=>'38',
    '5'=>'40',
    '6'=>'42',
    '7'=>'44',
);

$arrayNew=array(
    '2'=>'32',
    '1'=>'34',
    '3'=>'36',
    '4'=>'38',
    '5'=>'46',
    '6'=>'42',
    '7'=>'44',
);

/**
 * Here we check if there is any difference in keys or values in two arrays
 * array_intersect_assoc - returns values that are same in both arrays checking values as well as keys
 * array_diff returns the difference between the arrayNew values and those same values in both arrays, returned by array_intersect_assoc
 */
$result = array_diff($arrayNew,array_intersect_assoc($arrayOld, $arrayNew));
print_r($result);


//result is:
Array ( 
    [2] => 32, 
    [1] => 34,
    [5] => 46,
)

/** 我们可以看到，值 32 和 34 的索引不同* 而索引 5 的值也从 40 变为 46*/