php - Doctrine Join Many To Many without association

Question

我有:两个具有单向 M:M 关联的实体。

class ShareInfo
{
    // ...

    /**
     * @ORM\ManyToMany(targetEntity="Item")
     * @ORM\JoinTable(name="share_info_items",
     *      joinColumns={@ORM\JoinColumn(name="share_id", referencedColumnName="id")},
     *      inverseJoinColumns={@ORM\JoinColumn(name="item_id", referencedColumnName="id")})
     *
     * @var Item[]
     */
    private $items;
}

class Item
{
    // ...

    // This entity has no association with ShareInfo,
    // because M:M is undirectional and defined in ShareInfo entity
}

我想要的:从items表(Item实体)中选取数据，其中Item和ShareInfo之间至少存在一条M:M记录。

我的建议不起作用(我有一个语义错误):

$queryBuilder
    ->select('i')
    ->from(Item::class, 'i')
    ->innerJoin(ShareInfo::class, 'shareInfo', 'WITH', 'shareInfo.items = i');

在纯 SQL 中，我会做这样的事情:

SELECT i.*
FROM items i
INNER JOIN share_info_items shareInfo
    ON shareInfo.item_id = i.id

不敢相信没有 DQL 模拟这个。我能想到的唯一解决方案是将单向 M:M 关联拆分为双向

附言这道题没有重复，我检查的很好。

Answer 1

实现这一点的方法是通过子查询:

$em=$this->getDoctrine()->getManager();
$queryBuilder1=$em->createQueryBuilder();
$queryBuilder1->select(array('DISTINCT i.id'))
          ->from('AppBundle:ShareInfo', 'share_info')
          ->innerJoin('share_info.items', 'i');
$queryBuilder=$em->createQueryBuilder();
$queryBuilder->select('i')
         ->from('AppBundle:items', 'i')
         ->where($queryBuilder->expr()
         ->in('i.id',$queryBuilder1->getDql()));