php - 解析谷歌日历 XML 提要

Question

我有来自公共(public)谷歌日历的 XML 提要。看起来像这样:

<?xml version='1.0' encoding='UTF-8'?>
    <feed xmlns='................' xmlns:gd='http://schemas.google.com/g/2005'>
        <id>http://www.google.com/calendar/feeds/........./public/full</id>
        <updated>2009-08-24T10:57:00.000Z</updated>
        <category scheme='http://schemas.google.com/g/2005#kind' term='http://schemas.google.com/g/2005#event'/>
            <title type='text'>Sports Events</title>
    .....
        <entry>
            <id>...........</id>
            <published>2009-08-14T00:29:58.000Z</published>
            <updated>2009-08-14T00:29:58.000Z</updated>
            <category scheme='http://schemas.google.com/g/2005#kind' term='http://schemas.google.com/g/2005#event'/>
..............
            <georss:where>
                <gml:Point>
                    <gml:pos>11.111111 -22.22222</gml:pos>
                </gml:Point>
            </georss:where>
            <gd:eventStatus value='http://schemas.google.com/g/2005#event.confirmed'/>
            <gd:transparency value='http://schemas.google.com/g/2005#event.transparent'/>
            <gCal:uid value='.........@google.com'/>
            <gCal:sequence value='0'/>
            <gd:when startTime='2009-10-03' endTime='2009-10-04'/>

.............

现在是PHP:

$calendar = simplexml_load_file('http://my.feed.com');
foreach ($calendar->entry as $item) {
    //here I get the whole <entry> node
    $gd = $item->children('http://schemas.google.com/g/2005');
    // now in $gd I have all nodes like <gd:XXXXX>
}

问题是如何从这里获取值(value)？

<gml:pos>11.111111 -22.22222</gml:pos>

它不存在于我的 $gd 变量中，如何获取该节点？

Answer 1

我强烈推荐使用这个库:https://github.com/collegeman/coreylib .这将使一切从开始到结束都变得非常容易。