php - 如何在 echo 调用中运行函数

Question

这是一个快速而简单的问题。我今天过得很糟糕，不知道该怎么做:

我需要做的是这个...

我正在检查 url 中的 PMD，如果是这样的话:

<?php 
        if ( isset($_GET['pmd']) ) { 
          echo"<div class=\"response\"><p style=\"width:350px; height:200px; vertical-align:middle;\"><strong>Thank you for acting as a &quot;watchman on the walls&quot; of Jerusalem! Your name will now appear on our virtual wall.<br><br>You can also catch up on the latest news from Israel by visiting our news feed below.</strong></p></div>";
        }else { etc...

我需要在其中包含一个像这样的图像，它正在发射一个跟踪像素。

<img src="url.com?cid=12345&aid=1234&oid=<?php echo mt_rand(); ?>&quantity=1" height="1" width="1" />

我想要的是:

<?php 
        if ( isset($_GET['pmd']) ) { 
          echo"<div class=\"response\"><p style=\"width:350px; height:200px; vertical-align:middle;\"><strong>Thank you for acting as a &quot;watchman on the walls&quot; of Jerusalem! Your name will now appear on our virtual wall.<br><br>You can also catch up on the latest news from Israel by visiting our news feed below.</strong></p>
          <br />
          <img src="url.com?cid=12345&aid=1234&oid=<?php echo mt_rand(); ?>&quantity=1" height="1" width="1" />
          </div>";
        }else {

我需要做什么才能触发 mt_rand() 函数？

谢谢，

马特

Answer 1

您可以改用此语法:

<?php if ( isset($_GET['pmd']) ): ?>
    <div class="response"><p style="width:350px; height:200px; vertical-align:middle;"><strong>Thank you for acting as a &quot;watchman on the walls&quot; of Jerusalem! Your name will now appear on our virtual wall.<br><br>You can also catch up on the latest news from Israel by visiting our news feed below.</strong></p>
      <br />
      <img src="url.com?cid=12345&aid=1234&oid=<?php echo mt_rand(); ?>&quantity=1" height="1" width="1" />
    </div>
<?php else: ?>
    etc
<?php endif; ?>