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php - 在数据透视查询中查找最后一个 "Non-Null"值

转载 作者:可可西里 更新时间:2023-11-01 12:59:10 25 4
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我有以下查询:

 SELECT * FROM 
(
SELECT unix_timestamp, input_raw, tag_id
from [200030].[dbo].inputs
WHERE inputs.date_time > dateadd(day,-1,getdate())
AND
(tag_id = 92164 or tag_id = 92149)
) src
pivot
(
max(input_raw)
FOR tag_id IN ([92164], [92149])
) piv
ORDER by unix_timestamp DESC

这很棒而且有效。它给了我结果:

enter image description here

但是,我希望查询为我再做一件事。

每当出现“NULL”结果时,我希望查询将“NULL”替换为列中最后一个“非 NULL”值。

例如,在“92164”列中看到的第一个 NULL 将替换为“211”。

此外,一行中可能会有多个“NULL”,因此查询需要继续向上查询该列,直到找到一个非 NULL。

我已经能够使用 php 完成此操作。将结果放入 2D 关联数组并运行一个查找空值的函数,然后循环查找最后一个非 NULL,但如果可能的话,我真的想在 SQL 中全部完成。我更愿意使用

while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC)){
//code
}

比分配几个数组的方法。

有什么帮助吗?

谢谢

//编辑

忘记补充一点,这仅适用于空值上方有任何非空值的情况。例如,如果第一行是 NULL 是可以接受的。

最佳答案

您可以将数据透视查询放在 CTE 中,并在确定要显示的值时重用 CTE。您的数据仅在第一列中有空值,但这里有一个版本可以处理两列中的空值。

WITH C AS
(
SELECT *
FROM (
SELECT unix_timestamp, input_raw, tag_id
FROM inputs
WHERE date_time > dateadd(day,-1,getdate()) AND
(tag_id = 92164 OR tag_id = 92149)
) src
PIVOT
(
MAX(input_raw)
FOR tag_id IN ([92164], [92149])
) piv
)
SELECT C1.unix_timestamp,
(
SELECT TOP(1) C2.[92164]
FROM C AS C2
WHERE C1.unix_timestamp <= C2.unix_timestamp AND
C2.[92164] IS NOT NULL
ORDER BY C2.unix_timestamp
) AS [92164],
(
SELECT TOP(1) C2.[92149]
FROM C AS C2
WHERE C1.unix_timestamp <= C2.unix_timestamp AND
C2.[92149] IS NOT NULL
ORDER BY C2.unix_timestamp
) AS [92149]
FROM C AS C1
ORDER by C1.unix_timestamp DESC;

如果您遇到性能问题,将 CTE 的结果存储在具有有用的聚集键索引的临时表中可能会更快。

CREATE TABLE #C
(
unix_timestamp int PRIMARY KEY,
[92164] int,
[92149] int
);

INSERT INTO #C
SELECT *
FROM (
SELECT unix_timestamp, input_raw, tag_id
FROM inputs
WHERE date_time > dateadd(day,-1,getdate()) AND
(tag_id = 92164 OR tag_id = 92149)
) src
PIVOT
(
MAX(input_raw)
FOR tag_id IN ([92164], [92149])
) piv;

SELECT C1.unix_timestamp,
(
SELECT TOP(1) C2.[92164]
FROM #C AS C2
WHERE C1.unix_timestamp <= C2.unix_timestamp AND
C2.[92164] IS NOT NULL
ORDER BY C2.unix_timestamp
) AS [92164],
(
SELECT TOP(1) C2.[92149]
FROM #C AS C2
WHERE C1.unix_timestamp <= C2.unix_timestamp AND
C2.[92149] IS NOT NULL
ORDER BY C2.unix_timestamp
) AS [92149]
FROM #C AS C1
ORDER by C1.unix_timestamp DESC;

DROP TABLE #C;

关于php - 在数据透视查询中查找最后一个 "Non-Null"值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15093845/

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