javascript - 如何停止调用 window.open 覆盖函数的另一个函数

Question

我有一个函数，每当从 window.open 打开一个新选项卡时我都会调用该函数，因为我已经覆盖了该函数。还有，

I have attached a function on document.onclick event I need that function to be a pause or stop whenever window.open function runs.

我知道 event.stopPropagation();用于实现此目的，但在函数中，它不起作用，因为事件参数无法传递。

window.open = function(open) {
    return function(url) {
        console.log("url", url);
        
        // need to works here event.stopPropagation();
        return open.call(window, url);
    };
}(window.open);

document.onclick = clickListener;
function clickListener() {
  console.log("click");
};
function openLink(){
window.open('https://www.google.com')
}

<button onclick="openLink()">open link</button>

Answer 1

事件对象将在窗口上可用。您可以尝试以下操作:

    window.open = (function(open) {
    return function(url) {
        window.event.stopPropagation();
        console.log("url", url);

        // need to works here event.stopPropagation();
        return open.call(window, url);
    };
   })(window.open);