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php - 对两个目录重复图像计数

转载 作者:可可西里 更新时间:2023-11-01 12:48:17 25 4
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我正在使用 PHP 中的 glob 函数来浏览目录并尝试仅匹配图像文件。这是可行的,但是当我尝试计算每个目录中的图像时,它会为其他目录重复第一个目录的计数。例如,目录 1 有 6 张图像,目录 2 有 4 张图像,但是当我尝试显示每个目录的计数时,它显示目录 2 的 6 张图像,依此类推。

这是我的代码:

public function viewphotoalbumsAction()
{
$identity = $this->identity();
$dirname = array();
$files = array();

foreach (glob(getcwd() . '/public/images/profile/' . $identity . '/albums/*', GLOB_ONLYDIR) as $dir) {
$dirname[] = basename($dir);

foreach (glob($dir . '/*.{jpg,png,gif}', GLOB_BRACE) as $images) {
$files[] = $images;
}
}
//var_dump($files); exit;

$data = array(
'albums' => array_values($dirname),
'files' => $files,
);

return new ViewModel(array('album' => $data['albums'], 'files' => $data['files']));
}

var_dump()的结果

 array(9) { [0]=> string(96) "C:\xampp\htdocs/public/images/profile/fooboy/albums/bone mom's album_2017-07-03/massive snow.jpg"
[1]=> string(91) "C:\xampp\htdocs/public/images/profile/fooboy/albums/bone mom's album_2017-07-03/mom-jon.jpg"
[2]=> string(90) "C:\xampp\htdocs/public/images/profile/fooboy/albums/bone mom's album_2017-07-03/sunset.jpg"
[3]=> string(85) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/cref.jpg"
[4]=> string(88) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/diploma.jpg"
[5]=> string(86) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/eeyor.jpg"
[6]=> string(93) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/frother-jaws.jpg"
[7]=> string(88) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/frother.jpg"
[8]=> string(93) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/goat_singing.jpg" }

它正在按预期从每个目录获取所有图像,但我真正需要做的是将图像分开,这样我就可以对每个目录进行准确计数,而不仅仅是让它显示整个计数 (9)

查看代码:

<div class="w3-col m7">
<div class="w3-row-padding">
<div class="w3-col m12">
<div class="w3-card-2 w3-round w3-white">
<div class="w3-container w3-padding" id="view-photo-albums">
<p class="w3-center">Current Albums</p>
<br>
<?php
foreach ($this->album as $albums):
?>
<p>
<?php echo $albums; ?> - Number of images: <?php echo $this->files; ?>
</p>
<?php endforeach; ?>
</div>
</div>
</div>
</div>
</div>

如有任何帮助,我们将不胜感激。

更新:
我不能像对$data['albums']那样对$data['files']使用array_values给出数组到字符串转换的警告。

最佳答案

这段代码有问题:

foreach (glob($dir . '/*.{jpg,png,gif}', GLOB_BRACE) as $images) {
$files[] = $images;
}

变量 $dir 用于迭代第一次调用 glob() 返回的数组:

foreach (glob(...) as $dir) {
...
}

它在第一个 foreach 循环结束后的值是在 foreach 循环中分配给它的最后一个值。

最后,$data['albums'] 包含所有目录名称,$data['files'] 包含最后一个目录中的文件名称$data['albums'] 中列出的目录。

I cannot use array_values for $data['files'] as I did for $data['albums'] as it is giving a warning of array to string conversion.

array_values()不会为 $dirname$files 生成任何新内容。如果它们被创建(!),这两个变量包含由以 0 开头的序列号索引的值;这正是 array_values() 返回的内容。

您发布的代码的意图对我来说不是很清楚。我假设您想显示相册列表以及每个相册包含多少张图像。

我会这样做:

public function viewphotoalbumsAction()
{
$identity = $this->identity();

// Always initialize the arrays before putting values into them.
// Without this, if the first glob() returns an empty array, the outer
// foreach loop never runs and both $dirname and $files end up being undefined
// and this produces trouble in the code that uses these variables later.
$dirname = array();
// This will be a two dimensional array. It is indexed by directory
// names and contains the lists of files for each directory.
$files = array();

// The outer loop enumerates the albums
foreach (glob(getcwd() . '/public/images/profile/' . $identity . '/albums/*', GLOB_ONLYDIR) as $dir) {
// The directory name is the album name
$albumName = basename($dir);

// Put the album name in $dirname[]
// This is not really needed as we also have the album name
// as key in $files but can be useful if you want to keep more
// information about each album
$dirname[] = $albumName;

// Initialize the list of images of this album
$files[$albumName] = array();

// The inner loop enumerates the images of this directory
foreach (glob($dir . '/*.{jpg,png,gif}', GLOB_BRACE) as $images) {
$files[] = $images;
}
}

// Prepare the data for display
$data = array(
'albums' => $dirname,
'files' => $files,
);

return new ViewModel($data);
}

View (忽略了 HTML 包装器,就这样没问题):

<?php foreach ($this->files as $albumName => $listFiles): ?>
<p>
<?php echo $albumName; ?> - Number of images: <?php echo count($listFiles); ?>
</p>
<?php endforeach; ?>

需要注意的是,内部的 foreach 循环甚至都不需要,因为它所做的只是将 glob() 返回的数组中的值一个一个地复制到一个新数组。

glob() 返回的值存储到 $files[$albumName] 中会更快、更容易阅读和理解。由于存储在 $dirname 中的值从未被使用过,因此可以完全省略该变量并且函数变得更短(省略注释):

public function viewphotoalbumsAction()
{
$identity = $this->identity();
$files = array();

foreach (glob(getcwd().'/public/images/profile/'.$identity.'/albums/*', GLOB_ONLYDIR) as $dir) {
$albumName = basename($dir);
$files[$albumName] = glob($dir . '/*.{jpg,png,gif}', GLOB_BRACE);
}

return new ViewModel(array('files' => $files));
}

关于php - 对两个目录重复图像计数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44893586/

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