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php - zend 不使用列,并选择所有内容

转载 作者:可可西里 更新时间:2023-11-01 12:48:15 26 4
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我有以下代码

$result = $handle->select()->from('store_details')
->where('store_details.store_id=?', $id)
->columns('store_details.store_name');
//->query(ZEND_DB::FETCH_OBJ);

但是,当我运行它时,整行都被选中,而不仅仅是我想要的列。这是 __toString

的输出
SELECT `store_details`.*, `store_details`.`store_name` 
FROM `store_details` WHERE (store_details.store_id=8)

有什么帮助吗?

最佳答案

columns() 方法用于添加 列到现有的fromjoin。构建查询的正确方法是:

$result = $handle->select()->from('store_details','store_details.store_name')->where('store_details.store_id=?', $id);

您需要将所需的列指定为 from() 方法的第二个参数,如果它只是一列则为字符串,或者为多列则为数组。来自Zend_Db_Select docs :

In the second argument of the from() method, you can specify the columns to select from the respective table. If you specify no columns, the default is "*", the SQL wildcard for "all columns".

You can list the columns in a simple array of strings, or as an associative mapping of column alias to column name. If you only have one column to query, and you don't need to specify a column alias, you can list it as a plain string instead of an array.

关于php - zend 不使用列,并选择所有内容,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1023789/

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