php - 通过 PHP 从 NTP 服务器检索时间

Question

我的虚拟机 (VMWare/Ubuntu) 出现时间不同步的问题。我们决定最好的办法是直接从 NTP 服务器获取时间，所以我开始研究一个脚本来做到这一点，但到目前为止没有任何效果，这就是为什么我决定来这里看看是否有人能指出我正确的地方方向。

澄清一下，我正在寻找一种通过 PHP 连接到时间服务器的方法，以直接检索时间并在我需要生成的时间戳上重复使用它，而不是同步服务器。

Answer 1

这是一个完整的工作代码:

<?php
error_reporting(E_ALL ^ E_NOTICE);
ini_set("display_errors", 1);

date_default_timezone_set("America/Argentina/Buenos_Aires");

/* Query a time server (C) 1999-09-29, Ralf D. Kloth (QRQ.software) <ralf at qrq.de> */
function query_time_server ($timeserver, $socket)
{
    $fp = fsockopen($timeserver,$socket,$err,$errstr,5);
        # parameters: server, socket, error code, error text, timeout
    if($fp)
    {
        fputs($fp, "\n");
        $timevalue = fread($fp, 49);
        fclose($fp); # close the connection
    }
    else
    {
        $timevalue = " ";
    }

    $ret = array();
    $ret[] = $timevalue;
    $ret[] = $err;     # error code
    $ret[] = $errstr;  # error text
    return($ret);
} # function query_time_server


$timeserver = "ntp.pads.ufrj.br";
$timercvd = query_time_server($timeserver, 37);

//if no error from query_time_server
if(!$timercvd[1])
{
    $timevalue = bin2hex($timercvd[0]);
    $timevalue = abs(HexDec('7fffffff') - HexDec($timevalue) - HexDec('7fffffff'));
    $tmestamp = $timevalue - 2208988800; # convert to UNIX epoch time stamp
    $datum = date("Y-m-d (D) H:i:s",$tmestamp - date("Z",$tmestamp)); /* incl time zone offset */
    $doy = (date("z",$tmestamp)+1);

    echo "Time check from time server ",$timeserver," : [<font color=\"red\">",$timevalue,"</font>]";
    echo " (seconds since 1900-01-01 00:00.00).<br>\n";
    echo "The current date and universal time is ",$datum," UTC. ";
    echo "It is day ",$doy," of this year.<br>\n";
    echo "The unix epoch time stamp is $tmestamp.<br>\n";


    echo date("d/m/Y H:i:s", $tmestamp);
}
else
{
    echo "Unfortunately, the time server $timeserver could not be reached at this time. ";
    echo "$timercvd[1] $timercvd[2].<br>\n";
}
?>

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