linux - 如何使用 cURL 从文件中读取标题？

Question

我找到了 this .

我写了这个变体:

#!/bin/bash
while read line ; do
  headers="$headers -H '$line'"
done < public/headers.txt
echo $headers
curl -X PUT \
     $headers \
     -d @'public/example.json' \
     echo.httpkit.com

在 headers.txt 我有:

X-PAYPAL-SECURITY-USERID:123
X-PAYPAL-SECURITY-PASSWORD:123

但是当我运行 ./public/curl.sh 时，我没有收到我发送的 header 。

我用环境变量隔离了这个问题:

$ x='-H some:asd'
$ curl $x echo.httpkit.com
=> header was NOT present
$ curl -H 'some:asd' echo.httpkit.com
=> header was present
$ curl -H some:asd echo.httpkit.com
=> header was present

如何在 header 部分正确插入变量？

Answer 1

让我们问shellcheck :

In yourscript line 3:
  headers="$headers -H '$line'"
                       ^-- SC2089: Quotes/backslashes will be treated literally. 
                                   Use an array.

好吧，那我们开始吧

#!/bin/bash
while read line ; do
headers=("${headers[@]}" -H "$line")
done < public/headers.txt
echo "${headers[@]}"
curl -X PUT \
   "${headers[@]}" \
   -d @'public/example.json' \
   echo.httpkit.com

结果:

{
  "method": "PUT",
  "uri": "/",
  "path": {
    "name": "/",
    "query": "",
    "params": {}
  },
  "headers": {
    "host": "echo.httpkit.com",
    "user-agent": "curl/7.35.0",
    "accept": "*/*",
    "x-paypal-security-userid": "123",      //      <----- Yay!!
    "x-paypal-security-password": "123",
    "content-length": "32",
    "content-type": "application/x-www-form-urlencoded"
  },
  "body": "\"This is text from example.json\"",
  "ip": "127.0.0.1",
  "powered-by": "http://httpkit.com",
  "docs": "http://httpkit.com/echo"
}