redis - 如何使用键与 express 列表不匹配的正则表达式删除 redis？

Question

我尝试在redis中删除行，我首先搜索键以确保我的表达是正确的。

获取以 sess: 开头的键:

keys sess:*   //I get return as I expect

获取不以 sess: 开头的键:

keys ^(sess:)* //I get empty list, not as expect
keys [^sess:]* //I get list that not start with s or e or :, not as expect

获取不以sess:和brand:开头的key

keys [^(sess:|brand:)]* //I get list that not start with s or e or : or b and so on, not as expect

谁能帮我列出我没有得到预期正确返回的 list ？

Answer 1

如果您要引用keys 命令的文档 here你会注意到参数

Supported glob-style patterns: h?llo matches hello, hallo and hxllo h*llo matches hllo and heeeello h[ae]llo matches hello and hallo, but not hillo h[^e]llo matches hallo, hbllo, ... but not hello h[a-b]llo matches hallo and hbllo Use \ to escape special characters if you want to match them verbatim.

因此不支持正则表达式

如文档中所述:

If you're looking for a way to find keys in a subset of your keyspace,consider using SCAN or sets

Link to glob-style patterns here