windows - 获取文本文件中两个单词之间的文本

Question

为简洁起见，我有一个如下所示的文本文件(在 Windows 中):

Blah Blah Blah Blah
Blah Blah Blah 2016
START-OF-FILE
ABC
ABCDE Blah Blah Blah
Blah Blah Blah Blah
Blah Blah Blah Blah Blah Blah
END-OF-FILE
Blah Blah Blah
Blah Blah Blah

我只想要 START-OF-FILE 和 END-OF-FILE 之间的文本

ABC
ABCDE Blah Blah Blah
Blah Blah Blah Blah
Blah Blah Blah Blah Blah Blah

我尝试使用 Findstr，但效果不佳。有人可以帮忙吗？

这是我目前所拥有的:

@echo off
setlocal enabledelayedexpansion

set quote=

for /f "tokens=*" %%a in (infile.txt) do (
  set str=%%a
  set str=!str:"=:!

  if not "!str!"=="!str::=!" (
    if defined quote (
      set quote=
      for %%b in (^"%%a) do set str=%%~b
      if not "!str!"==START-OF-FILE if not "!str: =!"==END-OF-FILE echo !str! >> outfile.txt
    ) else (
      set quote=1
      for %%b in (%%a^") do set str=%%~b
    )
  )

  if defined quote (
    if not "!str!"==START-OF-FILE if not "!str: =!"==END-OF-FILE echo !str! >> outfile.txt
  )
)

这是结果:

2016" 
START-OF-FILE 
ABC
ABCDE Blah Blah Blah
Blah Blah Blah Blah
Blah Blah Blah Blah Blah Blah
END-OF-FILE
Blah Blah Blah

我需要不包含 2016"、START-OF-FILE 、END-OF-FILE 和 END-OF-FILE (Blah Blah Blah) 之后的行

Answer 1

@echo off
setlocal EnableDelayedExpansion

set "skip="
for /F "delims=:" %%a in ('findstr /N "START-OF-FILE END-OF-FILE" input.txt') do (
   if not defined skip (
      set "skip=%%a"
   ) else (
      set /A "lines=%%a-skip-1"
   )
)
(for /F "skip=%skip% delims=" %%a in (input.txt) do (
   echo %%a
   set /A lines-=1
   if !lines! equ 0 goto break
)) > output.txt
:break