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laravel - 渲染 View 作为事件广播的响应

转载 作者:可可西里 更新时间:2023-11-01 11:25:04 25 4
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您好,我正在开发一个 Laravel 网络应用程序,该应用程序使用事件广播 troug redis 和 socket.io。一切正常,但我试图返回渲染 View 作为事件的响应。Mi事件是这样的:

    <?php

namespace App\Events;

use Illuminate\Broadcasting\Channel;
use Illuminate\Queue\SerializesModels;
use Illuminate\Broadcasting\PrivateChannel;
use Illuminate\Broadcasting\PresenceChannel;
use Illuminate\Foundation\Events\Dispatchable;
use Illuminate\Broadcasting\InteractsWithSockets;
use Illuminate\Contracts\Broadcasting\ShouldBroadcast;

class EventName implements ShouldBroadcast
{
use Dispatchable, InteractsWithSockets, SerializesModels;

/**
* Create a new event instance.
*
* @return void
*/

public $data;

public function __construct()
{
$this->data = array(
'power'=> 'Funziona',
'view'=> view('dashboard.partials.messages')->render()
);
}

/**
* Get the channels the event should broadcast on.
*
* @return \Illuminate\Broadcasting\Channel|array
*/
public function broadcastOn()
{
return ['test-channel'];
}
}

我使用这段代码在页面上呈现响应:

<script src="/frontend/socket.io.js"></script>
<script>
var socket = io('http://1clickfashion.com:3002');
socket.on("test-channel:App\\Events\\EventName", function(message){
// increase the power everytime we load test route
alert(message.data.power);
$('#messages').html('');
$('#messages').html(message.data.view);

});
</script>

“电源”警报显示正确,但 View 不工作。在另一个 View 中,我将 View 用作 return response()->json($view) 并且工作完美......有人有类似的问题吗?

最佳答案

对于在这个问题上挣扎的任何人,通过将 View 作为在 Controller 中呈现的变量传递来解决。像这样。

在 Controller 中:

$view = view('dashboard.partials.messages')->with('post', $post_c)->render();
event(new \App\Events\Post($view));

在事件中:

 public $data;

public function __construct($view)
{
$this->data = array(
'view'=> $view
);
}

关于laravel - 渲染 View 作为事件广播的响应,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46812754/

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