javascript - redis 处理 'N' 没有连接的能力？

Question

如果有任何关于 Redis 的性能测量它可以同时处理多少个订阅/ channel ？

Answer 1

我还没有看到这方面的基准，但推送到订阅 channel 的复杂性在 O(N) 系列中。来自文档:

发布:

O(N+M) where N is the number of clients subscribed to the
receiving channel and M is the total number of subscribed 
patterns (by any client).

PSUBSCRIBE(订阅模式):

O(N) where N is the number of patterns the client is already subscribed to.

订阅:

O(N) where N is the number of channels to subscribe to.