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mongoDB 聚合 : $addToSet then $sort

转载 作者:可可西里 更新时间:2023-11-01 10:36:26 26 4
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我正在尝试对来自 mongoDB 集合(使用 nodeJS 驱动程序)的多个字段中的数组中的唯一值进行排序。

一个小数据集:

[{
"_id" : "5c93db3dd0184516406013f7",
"filters" : {
"genres" : [
{
"_id" : "9CXBYc4qP8sqcNMZ5",
"fr" : "Art Abstrait",
"en" : "Abstract Art",
"de" : "Abstrakte Kunst",
"it" : "Arte astratta",
"es" : "Arte Abstracto"
}
],
"subjects" : [
{
"_id" : "3QjL6YSfmuY6NFHGG",
"fr" : "Abstrait",
"en" : "Abstract",
"de" : "Abstrakt",
"it" : "Astratto",
"es" : "Abstracto"
}
],
"type" : {
"_id" : "CYK2WcepkJsy5xXMo",
"fr" : "Gravure au carborundum",
"en" : "Carborundum etching",
"de" : "Carborundum Radierung",
"it" : "Incisione carborandum",
"es" : "Grabado al Carborundum"
}
}
},
{
"_id" : "5c93db3ed0184516406013f8",
"filters" : {
"genres" : [
{
"_id" : "9CXBYc4qP8sqcNMZ5",
"fr" : "Art Abstrait",
"en" : "Abstract Art",
"de" : "Abstrakte Kunst",
"it" : "Arte astratta",
"es" : "Arte Abstracto"
}
],
"subjects" : [
{
"_id" : "3QjL6YSfmuY6NFHGG",
"fr" : "Abstrait",
"en" : "Abstract",
"de" : "Abstrakt",
"it" : "Astratto",
"es" : "Abstracto"
}
],
"type" : {
"_id" : "CYK2WcepkJsy5xXMo",
"fr" : "Gravure au carborundum",
"en" : "Carborundum etching",
"de" : "Carborundum Radierung",
"it" : "Incisione carborandum",
"es" : "Grabado al Carborundum"
}
}
},
{
"_id" : "5c93e19ed018451640601da6",
"filters" : {
"genres" : [
{
"_id" : "9CXBYc4qP8sqcNMZ5",
"fr" : "Art Abstrait",
"en" : "Abstract Art",
"de" : "Abstrakte Kunst",
"it" : "Arte astratta",
"es" : "Arte Abstracto"
}
],
"subjects" : [
{
"_id" : "3QjL6YSfmuY6NFHGG",
"fr" : "Abstrait",
"en" : "Abstract",
"de" : "Abstrakt",
"it" : "Astratto",
"es" : "Abstracto"
}
],
"type" : {
"_id" : "KfGWEHL2pAto8nfze",
"fr" : "Gravure",
"en" : "Etching",
"de" : "Radierung",
"it" : "Incisione",
"es" : "Grabado"
}
}
}]

我的查询结果(lang = 'en'):

{
"subjects": [
{
"_id": "3QjL6YSfmuY6NFHGG",
"fr": "Abstrait",
"en": "Abstract",
"de": "Abstrakt",
"it": "Astratto",
"es": "Abstracto"
},
{
"_id": "3QjL6YSfmuY6NFHGG",
"fr": "Abstrait",
"en": "Abstract",
"de": "Abstrakt",
"it": "Astratto",
"es": "Abstracto"
}
],
"genres": [
{
"_id": "9CXBYc4qP8sqcNMZ5",
"fr": "Art Abstrait",
"en": "Abstract Art",
"de": "Abstrakte Kunst",
"it": "Arte astratta",
"es": "Arte Abstracto"
},
{
"_id": "9CXBYc4qP8sqcNMZ5",
"fr": "Art Abstrait",
"en": "Abstract Art",
"de": "Abstrakte Kunst",
"it": "Arte astratta",
"es": "Arte Abstracto"
}
],
"types": [
{
"_id": "CYK2WcepkJsy5xXMo",
"fr": "Gravure au carborundum",
"en": "Carborundum etching",
"de": "Carborundum Radierung",
"it": "Incisione carborandum",
"es": "Grabado al Carborundum"
},
{
"_id": "KfGWEHL2pAto8nfze",
"fr": "Gravure",
"en": "Etching",
"de": "Radierung",
"it": "Incisione",
"es": "Grabado"
}
]
}

聚合管道:

[
{ $unwind: '$filters.subjects' },
{ $unwind: '$filters.genres' },
{ $group: {
_id: null,
subjects: { $addToSet: '$filters.subjects' },
types: { $addToSet: '$filters.type' },
genres: { $addToSet: '$filters.genres' },
}},
{ $unwind: '$subjects' },
{ $unwind: '$genres' },
{ $unwind: '$types' },
{ $sort: {
[`subjects.${lang}`]: 1,
[`types.${lang}`]: 1,
[`genres.${lang}`]: 1,
}},
{ $group: {
_id: null,
subjects: { $push: '$subjects' },
types: { $push: '$types' },
genres: { $push: '$genres' },
}},
{ $project: {
_id: false,
subjects: '$subjects',
types: '$types',
genres: '$genres'
}}
]

而不是像这样获取唯一值的排序数组:[A, B, C, D, ...]

我得到具有非唯一值的排序数组,如下所示:[A, A, A, B, B, B, C, C, C, D, D, D, ...]

使 $addToSet 分组无用。

知道我错了什么吗?

最佳答案

您遇到的问题是每个 $unwind 都将使用您正在展开的数组中的单个数组元素创建文档的副本。你有以下内容:

...
{ $unwind: '$subjects' },
{ $unwind: '$genres' },
{ $unwind: '$types' },
...

因此,首先要展开 subjects,它会为 subjects 中的每个元素生成一个文档,我们将其称为 subject。因此,我们为每个 subject 都有一个文档,它们本身包含数组 genrestypes。接下来展开 genres 时,每个 subject 文档都会展开以包含来自 genres 的元素 genre。这会使用每个 subjectgenres.length 副本——也就是说,每个 subject 都根据数组中有多少 genres 进行复制.展开 types 时会发生类似的情况。

简而言之,您在每次调用 $unwind 时都会复制您的数据。

用一个更简单的例子来说明:

// Doc:
{
ints: [1, 2],
alpha: ['a', 'b', 'c']

}

// Pipeline:
[
{ $unwind: "$ints" },
{ $unwind: "$alpha" }

]

// After unwinding "ints":
[
{ ints: 1, alpha: ['a', 'b', 'c'] },
{ ints: 2, alpha: ['a', 'b', 'c'] }

]

// After unwinding "alpha":
[
{ ints: 1, alpha: 'a' },
{ ints: 1, alpha: 'b' },
{ ints: 1, alpha: 'c' },
{ ints: 2, alpha: 'a' },
{ ints: 2, alpha: 'b' },
{ ints: 2, alpha: 'c' }
]

// Result: 3 duplicates of each value in "ints", 2 duplicates of each value in "alpha".

为了解决这个问题,我立即想到了几个选项:
1. 你可以$unwind一个数组,$sort它,$group结果到$push元素返回数组,对每个数组单独重复,一次一个。请注意,您需要使用 $first 运算符在分组时仅获取每个重复数组的一个副本。
2. 您可以将最后一个 $group 管道阶段更改为使用 $addToSet 而不是 $push 操作。

可能还有其他选项可供您使用,但以上任一选项都足以快速解决问题。

关于mongoDB 聚合 : $addToSet then $sort,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56409219/

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