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MongoDB 对同一文档中多个字段的结果进行分组和计算

转载 作者:可可西里 更新时间:2023-11-01 09:47:46 26 4
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关于 MongoDB 聚合框架,我能得到你的帮助吗?我试图从以下游戏集合中构建一个英超联赛表:

{ 
"_id" : ObjectId("5b39fec4b5f8df161d259f36"),
"gameWeek" : 1,
"homeTeam" : "Arsenal",
"awayTeam" : "Leicester",
"homeGoals" : 2,
"awayGoals" : 1
}, {
"_id" : ObjectId("5b39ffc2b5f8df161d259f6d"),
"gameWeek" : 2,
"homeTeam" : "Arsenal",
"awayTeam" : "Sunderland",
"homeGoals" : 1,
"awayGoals" : 1
}, {
"_id" : ObjectId("5b39ffe8b5f8df161d259f7f"),
"gameWeek" : 2,
"homeTeam" : "Sunderland",
"awayTeam" : "Manchester United",
"homeGoals" : 1,
"awayGoals" : 1
}, {
"_id" : ObjectId("5b492cbea5aef964f0911cce"),
"gameWeek" : 1,
"homeTeam" : "Manchester United",
"awayTeam" : "Leicester",
"homeGoals" : 0,
"awayGoals" : 1
}

我希望得到如下结果:

{ 
"_id" : "Arsenal",
"team" : "Arsenal",
"gamesPlayed" : 2,
"goalsFor" : 3,
"goalsAgainst" : 2,
"goalsDifference" : 1,
"gamesWon" : 1,
"gamesDraw" : 1,
"gamesLost" : 0,
"points" : 4
}, {
"_id" : "Leicester",
"team" : "Leicester",
"gamesPlayed" : 2,
"goalsFor" : 2,
"goalsAgainst" : 2,
"goalsDifference" : 0,
"gamesWon" : 1,
"gamesDraw" : 0,
"gamesLost" : 1,
"points" : 3
}, {
"_id" : "Sunderland",
"team" : "Sunderland",
"gamesPlayed" : 2,
"goalsFor" : 2,
"goalsAgainst" : 2,
"goalsDifference" : 0,
"gamesWon" : 0,
"gamesDraw" : 2,
"gamesLost" : 0,
"points" : 2
}, {
"_id" : "Manchester United",
"team" : "Manchester United",
"gamesPlayed" : 2,
"goalsFor" : 1,
"goalsAgainst" : 2,
"goalsDifference" : -1,
"gamesWon" : 0,
"gamesDraw" : 1,
"gamesLost" : 1,
"points" : 1
}

哪里:

  • gamesPlayed - 玩过的游戏总数,
  • goalsFor - 团队的总进球数,
  • goalsAgainst - 总进球数,
  • goalsDifference - 'goalsFor' 减去 'goalsAgainst'
  • 积分 - 每赢一场比赛得 3 分,平局得 1 分。

到目前为止,我有以下关于构建团队支持 homeTeam 结果的查询:

db.football_matches.aggregate([
{
$group: {
_id: "$homeTeam",
gamesPlayed : { $sum: NumberInt(1) },
goalsFor: { $sum: "$homeGoals" },
goalsAgainst: { $sum: "$awayGoals" },
gamesWon: { $sum: { $cond: { if: { $gt: [ "$homeGoals", "$awayGoals" ]}, then: NumberInt(1), else: NumberInt(0) } }},
gamesDraw: { $sum: { $cond: { if: { $eq: [ "$homeGoals", "$awayGoals" ]}, then: NumberInt(1), else: NumberInt(0) } }},
gamesLost: { $sum: { $cond: { if: { $lt: [ "$homeGoals", "$awayGoals" ]}, then: NumberInt(1), else: NumberInt(0) } }}
}
}, {
$project: {
team: "$_id" ,
gamesPlayed: "$gamesPlayed",
goalsFor: "$goalsFor",
goalsAgainst: "$goalsAgainst",
goalsDifference: { $subtract: [ "$goalsFor", "$goalsAgainst"] },
gamesWon: "$gamesWon",
gamesDraw: "$gamesDraw",
gamesLost: "$gamesLost",
points: { $add: [ {$multiply: [ "$gamesWon", NumberInt(3)]}, {$multiply: [ "$gamesDraw", NumberInt(1)]} ]}
}
}, {
$sort: { points: -1, goalsDifference: -1 }
}
])

理论上,我需要将以下分组结果与另一个类似的组语句结合起来,其中将对 awayTeam 字段执行类似的操作:

{
$group: {
_id: "$awayTeam",
gamesPlayed : { $sum: NumberInt(1) },
goalsFor: { $sum: "$awayGoals" },
goalsAgainst: { $sum: "$homeGoals" },
gamesWon: { $sum: { $cond: { if: { $gt: [ "$awayGoals", "$homeGoals" ]}, then: NumberInt(1), else: NumberInt(0) } }},
gamesDraw: { $sum: { $cond: { if: { $eq: [ "$awayGoals", "$homeGoals" ]}, then: NumberInt(1), else: NumberInt(0) } }},
gamesLost: { $sum: { $cond: { if: { $lt: [ "$awayGoals", "$homeGoals" ]}, then: NumberInt(1), else: NumberInt(0) } }}
}
}

我该怎么做?非常感谢你。如果之前有人问过类似的问题,请接受我的道歉。

最佳答案

您可以使用 $facet 尝试以下聚合, $replaceRoot , $unwind , $concatArrays最后还有一个$group阶段

db.collection.aggregate([
{ "$facet": {
"first": [
{ "$group": {
"_id": "$homeTeam",
"gamesPlayed": { "$sum": 1 },
"goalsFor": { "$sum": "$homeGoals" },
"goalsAgainst": { "$sum": "$awayGoals" },
"gamesWon": {
"$sum": { "$cond": { "if": { "$gt": [ "$homeGoals", "$awayGoals" ] }, "then": 1, "else": 0 } }
},
"gamesDraw": {
"$sum": { "$cond": { "if": { "$eq": [ "$homeGoals", "$awayGoals" ] }, "then": 1, "else": 0 } }
},
"gamesLost": {
"$sum": { "$cond": { "if": { "$lt": [ "$homeGoals", "$awayGoals" ] }, "then": 1, "else": 0 } }
}
}},
{ "$project": {
"team": "$_id",
"gamesPlayed": "$gamesPlayed",
"goalsFor": "$goalsFor",
"goalsAgainst": "$goalsAgainst",
"goalsDifference": { "$subtract": [ "$goalsFor", "$goalsAgainst" ] },
"gamesWon": "$gamesWon",
"gamesDraw": "$gamesDraw",
"gamesLost": "$gamesLost",
"points": { "$add": [{ "$multiply": [ "$gamesWon", 3 ] }, { "$multiply": [ "$gamesDraw", 1 ] }] }
}},
{ "$sort": { "points": -1, "goalsDifference": -1 } }
],
"second": [
{ "$group": {
"_id": "$awayTeam",
"gamesPlayed": { "$sum": 1 },
"goalsFor": { "$sum": "$awayGoals" },
"goalsAgainst": { "$sum": "$homeGoals" },
"gamesWon": {
"$sum": { "$cond": { "if": { "$gt": [ "$awayGoals", "$homeGoals" ] }, "then": 1, "else": 0 } }
},
"gamesDraw": {
"$sum": { "$cond": { "if": { "$eq": [ "$awayGoals", "$homeGoals" ] }, "then": 1, "else": 0 } }
},
"gamesLost": {
"$sum": { "$cond": { "if": { "$lt": [ "$awayGoals", "$homeGoals" ] }, "then": 1, "else": 0 } }
}
}},
{ "$project": {
"team": "$_id",
"gamesPlayed": "$gamesPlayed",
"goalsFor": "$goalsFor",
"goalsAgainst": "$goalsAgainst",
"goalsDifference": { "$subtract": [ "$goalsFor", "$goalsAgainst" ] },
"gamesWon": "$gamesWon",
"gamesDraw": "$gamesDraw",
"gamesLost": "$gamesLost",
"points": { "$add": [{ "$multiply": [ "$gamesWon",3 ] }, { "$multiply": [ "$gamesDraw",1 ] } ] }
}},
{ "$sort": { "points": -1, "goalsDifference": -1 } }
]
}},
{ "$project": {
"data": {
"$concatArrays": [ "$first", "$second" ]
}
}},
{ "$unwind": "$data" },
{ "$replaceRoot": { "newRoot": "$data" } },
{ "$group": {
"_id": "$_id",
"gamesPlayed": { "$sum": "$gamesPlayed" },
"goalsFor": { "$sum": "$goalsFor" },
"goalsAgainst": { "$sum": "$goalsAgainst" },
"gamesWon": { "$sum": "$gamesWon" },
"gamesDraw": { "$sum": "$gamesDraw" },
"gamesLost": { "$sum": "$gamesLost" }
}}
])

关于MongoDB 对同一文档中多个字段的结果进行分组和计算,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52060011/

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