windows - 如何从批处理文件中显示十六进制整数？

Question

echo The error level is: %ERRORLEVEL%

生产

>The error level is: 15

我想要什么:

>The error level is: F

我是否需要进行转换，或者有没有办法以不同方式显示数字？

感谢您在正确方向上提供的任何帮助，谢谢。

Answer 1

很久以前，我很无聊。

cmdcalc.cmd

@echo off
    if not defined trace set trace=rem
    %trace% on
SetLocal
    if "%1"=="/?" (
       call :help %0
       goto :eof
    )
    Set MinInBase=
    if /i "%2" EQU "Bin" call :DoBin %1
    if /i "%2" EQU "Hex" call :DoHex %1
    If not defined BinStr call :DoDec %1
EndLocal & set RET=%RET%
goto :eof


:DoBin
    Set MinInBase=2
    Set ShiftBy=1
    Set StartSyn=0b
    call :DoCalc %1
goto :eof

:DoHex
    Set MinInBase=16
    Set ShiftBy=4
    Set StartSyn=0x
    call :DoCalc %1
goto :eof


:DoDec
    if {%1} EQU {} goto :eof
    set  /a BinStr=%1
    set RET=%BinStr%
    echo %RET%
goto :eof


:DoCalc 
    Set BinStr= 
    SET /A A=%1
    %Trace% %A%
:StartSplit
    SET /A B="A>>%ShiftBy%"
    %Trace% %B%
    SET /A C="B<<%ShiftBy%"
    %Trace% %C%
    SET /A C=A-C
    %Trace% %C%
    call :StringIt %C%
    If %B% LSS %MinInBase% goto :EndSplit 
    set A=%B%
goto :StartSplit    
:EndSplit
    call :StringIt %B%
    set RET=%StartSyn%%BinStr%
    Echo %RET%
EndLocal & set RET=%RET%
goto :eof


:StringIt
    set Bin=0123456789ABCDEF
    FOR /F "tokens=*" %%A in ('echo "%%BIN:~%1,1%%"') do set RET=%%A
    set ret=%ret:"=%
    Set BinStr=%Ret%%BinStr%
goto :eof

:help
    echo %1 syntax:
    echo.
    echo %1 Calculation [Hex^|Bin]
    echo.
    echo eg %1 12*2 Hex
    echo.
    echo gives 0x18.
goto :eof