regex - 最后三个字母匹配字符串 "ces"

Question

我想知道如何在 mongodb 中仅使用其名称的最后三个字母来查找具有结构 db.collection.find() 的内容，谢谢!

  {  
    "address": {
      "building": "1007",
      "coord": [ -73.856077, 40.848447 ],
      "street": "Morris Park Ave",
      "zipcode": "10462"
    },
    "borough": "Bronx",
    "cuisine": "Bakery",
    "grades": [
      { "date": { "$date": 1393804800000 }, "grade": "A", "score": 2 },
      { "date": { "$date": 1378857600000 }, "grade": "A", "score": 6 },
      { "date": { "$date": 1358985600000 }, "grade": "A", "score": 10 },
      { "date": { "$date": 1322006400000 }, "grade": "A", "score": 9 },
      { "date": { "$date": 1299715200000 }, "grade": "B", "score": 14 }
    ],  
    "name": "Morris Park Bake Shop",
    "restaurant_id": "30075445"
  }

我目前的尝试:

db.mycollection.find({},{name:"ces"})

Answer 1

根据您的意思是“单词的最后三个字母” 还是“‘字段’的最后三个字母” 那么您通常需要 $regex

关于这个数据:

{ "_id" : ObjectId("570462448c0fd5187b53985a"), "name" : "Bounces" }
{ "_id" : ObjectId("5704624d8c0fd5187b53985b"), "name" : "Something" }
{ "_id" : ObjectId("5704625b8c0fd5187b53985c"), "name" : "Bounces Something" }

然后查询“word”，其中\b表示“word boundary”，在“string”表达式中通过\转义:

db.collection.find({ "name": { "$regex": "ces\\b" } })

哪些匹配:

{ "_id" : ObjectId("570462448c0fd5187b53985a"), "name" : "Bounces" }
{ "_id" : ObjectId("5704625b8c0fd5187b53985c"), "name" : "Bounces Something" }

或者查询“字段”，其中 $ 表示“从头开始”:

db.collection.find({ "name": { "$regex": "ces$" } })

哪些匹配:

{ "_id" : ObjectId("570462448c0fd5187b53985a"), "name" : "Bounces" }