c++ - 如何在不等待输入的情况下使用 getch()？

Question

 for (;;)
{
    cout << "You are playing for:" << playtime << "seconds." << endl;
    cout << "You have " << bytes << " bytes." << endl;
    cout << "You are compiling " << bps << " bytes per second." << endl;
    cout << "Press a to buy assembler monkey (produces 1 byte per second)/(cost 10 bytes)" << endl;
    switch(getch())
    {
        case 'a': bytes = bytes - 10; bps++; break;
    }
    bytes = bytes + bps;
playtime++;
Sleep(1000);
system("cls");
}

假设这是我的增量游戏。我想在 1 秒后刷新我的游戏。我怎样才能让 getch() 等待输入而不停止所有其他东西？

Answer 1

使用kbhit() 函数来检测是否按下了一个键:)

类似于:

 for (;;)
{
    cout << "You are playing for:" << playtime << "seconds." << endl;
    cout << "You have " << bytes << " bytes." << endl;
    cout << "You are compiling " << bps << " bytes per second." << endl;
    cout << "Press a to buy assembler monkey (produces 1 byte per second)/(cost 10 bytes)" << endl;
    if(kbhit()){  //is true when a key was pressed
        char c = getch();   //capture the key code and insert into c

        switch(c)
        {
            case 'a': bytes = bytes - 10; bps++; break;
        }
    }
    bytes = bytes + bps;
    playtime++;
    Sleep(1000);
    system("cls");
}