c# - 为什么这会导致 CS0695？

Question

public interface PipelineElement<in TIn, out TOut>
{
    IEnumerable<TOut> Run(IEnumerable<TIn> input, Action<Error> errorReporter);
}

public interface Stage
{
}

public abstract class PipelineElementBase<TIn, TOut> : PipelineElement<object, object>,
    PipelineElement<TIn, TOut> where TIn : Stage where TOut : Stage
{
    IEnumerable<object> PipelineElement<object, object>.Run(IEnumerable<object> input, Action<Error> errorReporter)
    {
        return this.Run(input.Cast<TIn>(), errorReporter).Cast<object>();
    }

    public abstract IEnumerable<TOut> Run(IEnumerable<TIn> input, Action<Error> errorReporter);
}

object没有实现 Stage , 因此既不 TIn也不TOut可能是object ， 正确的？那么为什么编译器会认为 PipelineElement<object, object>和 PipelineElement<TIn, TOut>可以变得相同吗？

编辑:是的，完全有可能多次实现相同的通用接口(interface):

public interface MyInterface<A> { }
public class MyClass: MyInterface<string>, MyInterface<int> { }

Answer 1

来自 Compiler Error CS0695

'generic type' cannot implement both 'generic interface' and 'generic interface' because they may unify for some type parameter substitutions.

This error occurs when a generic class implements more than one parameterization of the same generic interface, and there exists a type parameter substitution which would make the two interfaces identical. To avoid this error, implement only one of the interfaces, or change the type parameters to avoid the conflict.

你不能同时实现 PipelineElementBase<TIn, TOut>和 PipelineElement<object, object>抽象类的接口(interface)。

正如错误页面所说，你应该；

• 仅实现其中一项或
• 更改类型参数以避免冲突。

来自 C# 5.0 Language Specification

13.4.2 Uniqueness of implemented interfaces

The interfaces implemented by a generic type declaration must remain unique for all possible constructed types. Without this rule, it would be impossible to determine the correct method to call for certain constructed types. For example, suppose a generic class declaration were permitted to be written as follows:

interface I<T>
{
    void F();
}
class X<U,V>: I<U>, I<V>
{
    void I<U>.F() {...}
    void I<V>.F() {...}
}

Were this permitted, it would be impossible to determine which code to execute in the following case:

I<int> x = new X<int,int>();
x.F();

To determine if the interface list of a generic type declaration is valid, the following steps are performed:

• Let L be the list of interfaces directly specified in a generic class, struct, or interface declaration C.

• Add to L any base interfaces of the interfaces already in L.

• Remove any duplicates from L.

• If any possible constructed type created from C would, after type arguments are substituted into L, cause two interfaces in L to be identical, then the declaration of C is invalid. Constraint declarations are not considered when determining all possible constructed types.

In the class declaration X above, the interface list L consists of I<U> and I<V>. The declaration is invalid because any constructed type with U and V being the same type would cause these two interfaces to be identical types.

It is possible for interfaces specified at different inheritance levels to unify:

interface I<T>
{
  void F();
}
class Base<U>: I<U>
{
  void I<U>.F() {…}
}
class Derived<U,V>: Base<U>, I<V> // Ok
{
  void I<V>.F() {…}
}

This code is valid even though Derived<U,V> implements both I<U> and I<V>. The code

I<int> x = new Derived<int,int>();
x.F();

invokes the method in Derived, since Derived<int,int> effectively re-implements I<int>(§13.4.6).

[SO 编辑强调。]