MySQL在多列中选择最大值

Question

我有一个按日期列出股票价格的表格，我想选择最接近多个日期的值。例如，给我最接近今天、1 个月前和 2 个月前的价格。我可以在单独的语句中完成，是否可以在单个语句中完成？

在下面，我想返回最接近 2/7、1/7 和 d 12/7 日期的第 1、2 和 6 行(最好使用 abs() 来这样做？) .

+---+------------+---------+----------------+----------------+----------------+
| d | quotedate  |  price  | 2018-02-07diff | 2018-01-07diff | 2017-12-07diff |
+---+------------+---------+----------------+----------------+----------------+
| 1 | 2018-02-06 |  13.796 |             -1 |             30 |             61 |
| 2 | 2018-01-09 | 14.1135 |            -29 |              2 |             33 |
| 3 | 2018-01-02 |  13.822 |            -36 |             -5 |             26 |
| 4 | 2017-12-27 | 13.7365 |            -42 |            -11 |             20 |
| 5 | 2017-12-22 |   13.75 |            -47 |            -16 |             15 |
| 6 | 2017-12-04 |  13.589 |            -65 |            -34 |             -3 |
| 7 | 2017-11-28 |  13.477 |            -71 |            -40 |             -9 |
| 8 | 2017-10-31 |  13.214 |            -99 |            -68 |            -37 |
+---+------------+---------+----------------+----------------+----------------+

我已经让它完成 1 行，但我希望能够同时完成所有 3 行吗？ fiddle :Here

Answer 1

select p1.id, p1.name,
  DATE_FORMAT(p1.quote_date, "%Y-%m-%d") as quotedate,
  p1.price,
  DATEDIFF( p1.quote_date, '2018-02-07' ) as 'diff1',
  DATEDIFF( p1.quote_date, '2018-01-07' ) as 'diff2',
  DATEDIFF( p1.quote_date, '2017-12-07' ) as 'diff3'
from prices p1
left outer join (select id, name, quote_date, price, 
                 DATEDIFF( quote_date, '2018-02-07' ) as 'diff1p2'
                 FROM prices) p2
on (p1.name = p2.name
   AND DATEDIFF( p1.quote_date, '2018-02-07' )< diff1p2
    AND DATEDIFF( p1.quote_date, '2018-02-07' ) <=0


   )
WHERE p1.name = 'Stock1'
AND p2.id is null
union
    select p1.id, p1.name,
  DATE_FORMAT(p1.quote_date, "%Y-%m-%d") as quotedate,
  p1.price,
  DATEDIFF( p1.quote_date, '2018-02-07' ) as 'diff1',
  DATEDIFF( p1.quote_date, '2018-01-07' ) as 'diff2',
  DATEDIFF( p1.quote_date, '2017-12-07' ) as 'diff3'
from prices p1
left outer join (select id, name, quote_date, price, 
                 DATEDIFF( quote_date, '2018-01-07' ) as 'diff1p2'
                 FROM prices) p2
on (p1.name = p2.name
   AND DATEDIFF( p1.quote_date, '2018-01-07' )< diff1p2
    AND DATEDIFF( p1.quote_date, '2018-01-07' ) <=0

您应该在 3 个查询之间使用联合，以便一次获得所有 3 行