MySQL实现基于多个过滤器的搜索

Question

根据下面的表格结构，我希望能够提供基于属性组合的搜索过滤器:

表:动物属性

id      attributeId     animalId
1       455             55
2       999             55
3       685             55
4       999             89
5       455             89
6       333             93
7       685             93
8       999             93
--------------------------------

前端会有复选框，例如

Animal options

Colour
[ ] Black      (id 685)
[x] Brown      (id 999)

Body Covering
[ ] Fur        (id 233)
[ ] Scales     (id 333)
[x] Feathers   (id 455)

我希望上面的复选框选择所有棕色并且有羽毛的动物。我可以通过以下查询获取此数据:

SELECT animalId
FROM animalAttributes
WHERE attributeId IN (999,455)
GROUP BY animalId 
HAVING COUNT(DISTINCT attributeId) = 2;

我遇到的问题是从多个过滤器中选择了多个选项，例如

Animal options

Colour
[x] Black      (id 685)
[x] Brown      (id 999)

Body Covering
[x] Fur        (id 233)
[ ] Scales     (id 333)
[x] Feathers   (id 455)

我希望上面的复选框选择所有(黑色OR棕色)AND有(毛皮OR羽毛)的动物.我可以通过以下查询获取此数据:

SELECT animalId
FROM animalAttributes
WHERE
attributeId IN (685,233) ||
attributeId IN (685,455) ||
attributeId IN (999,233) ||
attributeId IN (999,455)
GROUP BY animalId 
HAVING COUNT(DISTINCT attributeId) = 2;

如果我想添加额外的过滤器，例如“有尾部”、“会飞”、“血型”等，我认为我需要计算所有组合 (cartesian product) 并遵循和上面的图案一样吗？例如5 个过滤器，每个过滤器都选择了 1 个或多个选项

attributeId IN (x,x,x,x,x) ||
attributeId IN (x,x,x,x,x) ||
attributeId IN (x,x,x,x,x) ||
...
HAVING COUNT(DISTINCT attributeId) = 5;

其他表格供引用

表:属性

attributeId    attributeCategoryId    attribute

233            1                      Fur
333            1                      Scales
455            1                      Feathers
685            2                      Black
999            2                      Brown
-----------------------------------------------

表:attributeCategories

attributeCategoryId    category
1                      Body covering
2                      Colour
------------------------------------

Answer 1

attributeId IN (685,233) ||
attributeId IN (685,455) ||
attributeId IN (999,233) ||
attributeId IN (999,455)

将与您编写的内容相同: attributeId IN (685,233,455,999,233)

尝试:

SELECT aa.animalId
FROM animalAttributes aa
LEFT JOIN attributes a ON a.attributeId = aa.attributeId
WHERE
(aa.attributeId IN (685,99) AND a.attributeCategoryId=1) AND
(aa.attributeId IN (223,455) AND a.attributeCAtegoryId=2)
GROUP BY animalId 

或者换句话说:(黑色或棕色和 isColor)和(毛皮或羽毛和 isBodyCovering)

未测试，但您应该明白了。