php - MySQL，按两个不同的列分组

Question

我的 table 看起来像:

╔═════╦═════════════════════╦═════════════════════╦═════════════╗
║ id  ║        begin        ║         end         ║ employeesId ║
╠═════╬═════════════════════╬═════════════════════╬═════════════╣
║   4 ║ 2015-11-11 00:00:00 ║ 2015-11-11 09:00:00 ║           8 ║
║  80 ║ 2015-11-11 09:00:00 ║ 2015-11-11 12:00:00 ║           8 ║
║  49 ║ 2015-11-11 00:00:00 ║ 2015-11-11 08:00:00 ║          61 ║
║  32 ║ 2015-11-11 08:00:00 ║ 2015-11-12 06:00:00 ║          61 ║
║  42 ║ 2015-11-12 07:00:00 ║ 2015-11-12 13:00:00 ║          61 ║
║  17 ║ 2015-11-11 00:00:00 ║ 2015-11-11 08:00:00 ║          22 ║
║  42 ║ 2015-11-11 09:00:00 ║ 2015-11-11 12:00:00 ║          22 ║
╚═════╩═════════════════════╩═════════════════════╩═════════════╝

我想合并列 employeesId 相等的行，并且一行的 begin 时间等于另一行的 end 时间。像这样:

╔═════════════════════╦═════════════════════╦═════════════╗
║        begin        ║         end         ║ employeesId ║
╠═════════════════════╬═════════════════════╬═════════════╣
║ 2015-11-11 00:00:00 ║ 2015-11-11 12:00:00 ║           8 ║
║ 2015-11-11 00:00:00 ║ 2015-11-12 06:00:00 ║          61 ║
║ 2015-11-12 07:00:00 ║ 2015-11-12 13:00:00 ║          61 ║
║ 2015-11-11 00:00:00 ║ 2015-11-11 08:00:00 ║          22 ║
║ 2015-11-11 09:00:00 ║ 2015-11-11 12:00:00 ║          22 ║
╚═════════════════════╩═════════════════════╩═════════════╝

编辑:

I need to merge continuous datetimes, in this example you can see that end time '2015-11-11 12:00:00' for employeesId = 8 replaced end time '2015-11-11 09:00:00' in first row because begin of the second row is equal to end of the first row.

Answer 1

尝试加入

SELECT a.`begin_date`, IF(b.`end_date` IS NOT NULL, b.`end_date`, a.`end_date`), a.`employer_id`
FROM `mytable` a
LEFT JOIN `mytable` b ON a.`employer_id` = b.`employer_id` AND a.`end_date` = b.`begin_date`
LEFT JOIN `mytable` c ON a.`employer_id` = c.`employer_id` AND a.`begin_date` = c.`end_date`
WHERE c.`id` IS NULL

但是你应该重建你的架构。