php - i nf数据表结构来自json数据

Question

我有一个像这样的数据库(mysql)表

id |  party  |  rights    | m_id
---+---------+------------+---------
9  |abc      | 3,5,6      | ["12,","15,"6"]
20 |xyz      |  5,2       | ["6,","2,"9","12"]
21 |xyz 1    |  5,2       | ["6,","9,"12"]

现在我想用这种方式制作我的 table 权利 5 的搜索结果是 ["12,","15,"6"] ["6","2,"12"] ["6","9,"12"]

12 | abc , xyz, xyz1 |

15 | abc|

6 | abc , xyz, xyz1 |

9 | xyz,xyz1 |

Answer 1

让我们从我认为您已经拥有的东西开始。这是 sscce .如果您调整 mysql 凭据，它应该在您的系统上运行，只创建一个临时 MySQL 表。它使用 PDO访问MySQL服务器。 您实际使用哪个 API 并不重要(即只要另一个 API 是 mysqli，因为 mysql_* 函数 are depreacted ;-))

<?php
$pdo = new PDO('mysql:host=localhost;dbname=test;charset=utf8', 'localonly', 'localonly', array(
    PDO::ATTR_EMULATE_PREPARES=>false,
    PDO::MYSQL_ATTR_DIRECT_QUERY=>false,
    PDO::ATTR_ERRMODE=>PDO::ERRMODE_EXCEPTION
));
setup($pdo);

$statement = $pdo->prepare('
    SELECT
        *
    FROM
        soFoo
    WHERE
        FIND_IN_SET(:right, rights)
');

$statement->execute( array(':right'=>5) );

/* in one way or another you have a loop where you fetch the records
having '5' in the `rights` field
*/
foreach( $statement as $row ) {
    echo $row['party'], ' ', $row['show_ids'], "\r\n";
}


function setup($pdo) {
    $pdo->exec('
        CREATE TEMPORARY TABLE soFoo
    (`id` int, `party` varchar(9), `exc` varchar(13), `rights` varchar(5), `show_ids` varchar(27))
   ');
  $pdo->exec( <<< eos
        INSERT INTO soFoo
            (`id`, `party`, `exc`, `rights`, `show_ids`)
        VALUES
            (9, 'Percept', 'Non-Exclusive', '3,5,6', '["12,","15,"6"]'),
            (20, 'Tata Sky', 'Non-Exclusive', '5,4,', '["6,","9,"11"]'),
            (21, 'Tata Sky', 'Exclusive', '5,4', '["6,","13","15,"2","4","9"]'),
            (22, 'Simbiotic', 'Exclusive', '6,2', '["12,","15,"1","6","7","8"]')
eos
    );
}

这打印

Percept ["12,","15,"6"]
Tata Sky ["6,","9,"11"]
Tata Sky ["6,","13","15,"2","4","9"]

并且(据我了解这个问题)就您已经掌握的情况而言。

现在让我们decode the JSON array并检查 whether it contains元素 9。如果它确实将当前行的信息添加到名为 $parties

的数组中

$parties = array();
/* in one way or another you have a loop where you fetch the records
having '5' in the `rights` field
*/
foreach( $statement as $row ) {
    $ids = json_decode($row['show_ids'], true);
    if ( in_array('9', $ids) ) {
        $parties[$row['id']] = $row['party'];
    }
}
var_export($parties);

打印

array (
  20 => 'Tata Sky',
  21 => 'Tata Sky',
)

但是......从关系数据库的角度来看，这是......次优的。
FIND_IN_SET 子句阻碍了 MySQL 有效地使用索引；您正在 单个字段中搜索(复合)数据。令人惊讶的是，数据库服务器实现可以提高性能；但它有限制。
并且您还将可能不需要的数据从 MySQL 服务器传输到 php 实例(那些在 rights 中具有 5 而不是 9 的记录show_ids)。如果可能，应避免这种情况。网络/网络堆栈速度很快并且可以优化，RAM 很便宜……但还是有限制。

所以，我建议你看看Database normalization一方面和/或document-oriented databases另一方面。