C# - 将十进制转换为 int32

Question

我有以下代码:

int a = Convert.ToInt32(4.5m);
int b = Convert.ToInt32(5.5m);

Console.WriteLine(a);
Console.WriteLine(b);

这是输出:

4
6

为什么 Convert.ToInt32 将十进制值舍入到最接近的偶数？

Answer 1

Convert 使用四舍五入或银行四舍五入:

The behavior of this method follows IEEE Standard 754, section 4. This kind of rounding is sometimes called rounding to nearest, or banker's rounding. It minimizes rounding errors that result from consistently rounding a midpoint value in a single direction.

To control the type of rounding used by the Round method, call the Math.Round(Double, MidpointRounding) overload.