php - Mysql到Mysqli

Question

如何从mysql切换到mysql i？因为我尝试了但是返回了一个空值。提前谢谢！
MySQL代码：

if(isset($_POST["username"])&& isset($_POST["password"])){

    $manager = preg_replace('#[^A-Za-z0-9]#i','',$_POST["username"]);
    $password = preg_replace('#[^A-Za-z0-9]#i','',$_POST["password"]);
    include "includes/connect_db.php";
    $sql = mysql_query("SELECT id FROM admin WHERE username='$manager'
        AND password=$password' LIMIT 1");

    $existCount = mysql_num_rows($sql);//count the row nums
    if($existCount == 1){//evaluate the count
        while($row=mysql_fetch_array($sql)){
            $id=$row["id"];
        }
        $_SESSION["id"] = $id;
        $_SESSION["manager"]=$manager;
        $_SESSION["password"]=$password;
        header("location:index.php");
        exit();

    }else{
        echo 'That information is incorrect, try again <a href="index.php">Click   Here</a>';
        exit();
    }

这是我以前尝试过的，但是显示了一条消息，mysqli_num_rows有布尔结果。
mysqli代码：

if(isset($_POST["username"])&& isset($_POST["password"])){

   $manager = preg_replace('#[^A-Za-z0-9]#i','',$_POST["username"]);
   $password = preg_replace('#[^A-Za-z0-9]#i','',$_POST["password"]); 
   include("includes/insert_db.php"); // i change the database connection
   $sql = "SELECT * FROM admin WHERE username='$manager' 
   AND password=$password'";

   $result = mysqli_query($con, $sql);

   $existCount = mysql_num_rows($result);//count the row nums
   if($existCount == 1){//evaluate the count
   while($row=mysqli_fetch_array($result)){
    $id=$row["id"];
   }
   $_SESSION["id"] = $id;
   $_SESSION["manager"]=$manager;
   $_SESSION["password"]=$password;
   header("location:index.php");
   exit();

  }else{
    echo 'That information is incorrect, try again <a href="index.php">Click Here</a>';
    exit(); 
  }
 }

Answer 1

尝试更改此：

$sql = mysql_query("SELECT id FROM admin WHERE username='$manager' 
AND password=$password' LIMIT 1");

对此：

$sql = "SELECT id FROM admin WHERE username='$manager' AND password='$password' LIMIT 1";

$result = mysqli_query($conn, $sql);

或者这个：

$sql = "SELECT id FROM admin WHERE username='$manager' AND password='$password' LIMIT 1"; 
$result = $conn->query($sql); 

（$conn是连接变量，如果不同，请更改它。）
希望这有帮助。
也将 mysql_fetch_array($sql)更改为 mysqli_fetch_array($sql)