gpt4 book ai didi

Mysql查询Order By太慢

转载 作者:可可西里 更新时间:2023-11-01 08:06:27 25 4
gpt4 key购买 nike

我知道以前有人问过这种问题,但没有一个让我找到解决方案。

这是我的查询:

SELECT p.photoid, c.comment, p.path, p.smallfile, p.bigfile, c.userid, c.dateposted, u.username, c.likephoto 
FROM bs_photocomments c, photos p, user u
WHERE c.active = 1
AND u.userid = c.userid
AND p.photoid = c.photoid
AND c.id = (SELECT ID FROM bs_photocomments WHERE photoid = p.photoid ORDER BY ID DESC LIMIT 1)
ORDER BY c.id DESC LIMIT 2

关于最后一个 AND 的一点解释:

基本上,我正在尝试获取 20 张独特照片的最新评论。例如,如果一张照片有 5 条评论,我只想显示最后一条。

ORDER BY c.id 是 killer 。只有 18 万条评论和 10 万张照片。如果我删除 ORDER BY 查询会立即返回,但显然不是我想要的结果。

索引如下:

+------------------+------------+--------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+------------------+------------+--------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| bs_photocomments | 0 | PRIMARY | 1 | id | A | 183269 | NULL | NULL | | BTREE | |
| bs_photocomments | 1 | photocomments_idx1 | 1 | photoid | A | 183269 | NULL | NULL | YES | BTREE | |
| bs_photocomments | 1 | photocomments_idx2 | 1 | active | A | 4 | NULL | NULL | YES | BTREE | |
| bs_photocomments | 1 | photocomments_idx3 | 1 | dateposted | A | 183269 | NULL | NULL | YES | BTREE | |
| bs_photocomments | 1 | photocomments_idx4 | 1 | userid | A | 4953 | NULL | NULL | YES | BTREE | |
| bs_photocomments | 1 | photocomments_idx5 | 1 | puserid | A | 4072 | NULL | NULL | YES | BTREE | |
| bs_photocomments | 1 | photocomments_idx6 | 1 | id | A | 183269 | NULL | NULL | | BTREE | |
| bs_photocomments | 1 | photocomments_idx6 | 2 | photoid | A | 183269 | NULL | NULL | YES | BTREE | |
| bs_photocomments | 1 | photocomments_idx7 | 1 | photoid | A | 183269 | NULL | NULL | YES | BTREE | |
| bs_photocomments | 1 | photocomments_idx7 | 2 | userid | A | 183269 | NULL | NULL | YES | BTREE | |
+------------------+------------+--------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+


+--------+------------+--------------+--------------+--------------+-----------+-------------+----------+--------+------+------------+---------+
| Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+--------+------------+--------------+--------------+--------------+-----------+-------------+----------+--------+------+------------+---------+
| photos | 0 | PRIMARY | 1 | photoid | A | 57736 | NULL | NULL | | BTREE | |
| photos | 1 | photos_idx1 | 1 | userid | A | 5773 | NULL | NULL | YES | BTREE | |
| photos | 1 | photos_idx2 | 1 | dateuploaded | A | 57736 | NULL | NULL | YES | BTREE | |
| photos | 1 | photos_idx3 | 1 | camera | A | 17 | NULL | NULL | YES | BTREE | |
| photos | 1 | photos_idx4 | 1 | focallength | A | 308 | NULL | NULL | YES | BTREE | |
| photos | 1 | photos_idx5 | 1 | category | A | 96 | NULL | NULL | YES | BTREE | |
| photos | 1 | photos_idx6 | 1 | active | A | 1 | NULL | NULL | YES | BTREE | |
| photos | 1 | photo_idx7 | 1 | aperture | A | 354 | NULL | NULL | YES | BTREE | |
| photos | 1 | photos_idx8 | 1 | lenstype | A | 1 | NULL | NULL | YES | BTREE | |
| photos | 1 | photos_idx9 | 1 | film | A | 1 | NULL | NULL | YES | BTREE | |
| photos | 1 | photos_idx10 | 1 | originalfile | A | 57736 | NULL | NULL | YES | BTREE | |
+--------+------------+--------------+--------------+--------------+-----------+-------------+----------+--------+------+------------+---------+

有什么想法吗?谢谢!

最佳答案

此查询将返回(最多)20 张不同照片的单个“最新”评论(“recent-cy”由 bs_photocomments 表中的升序 ID 值标识)。返回的 20 张照片将是评论最“最近”的照片,并从最“最近”的评论开始排序。 (注意:只考虑 bs_photocomments 中具有 active=1 的行,bs_photocomments 中的所有其他行都将被忽略,就好像它们甚至不在表中一样。)

SELECT p.photoid
, c.comment
, p.path
, p.smallfile
, p.bigfile
, c.userid
, c.dateposted
, u.username
, c.likephoto
JOIN (
SELECT n.photoid
, MAX(n.id) AS max_id
FROM bs_photocomments n
WHERE n.active = 1
GROUP BY n.photoid
ORDER BY max_id DESC
LIMIT 20
) m
JOIN bs_photocomments c
ON c.id = m.max_id
JOIN photos p
ON p.photoid = c.photoid
JOIN user u
ON u.userid = c.userid
ORDER BY c.id DESC
LIMIT 20

“技巧”是使用内联 View 来获取每个 photoid 的“最新”评论(内联 View 的别名是 m)。完成后,只需从 bs_photocomments 获取行,以及从用户和照片获取相关行即可。

我相信原始查询中真正的性能“ killer ”是连接谓词中的相关子查询。就对 bs_photocomments 表中的每一行执行该查询,甚至对 photos 表中的每一行运行该查询而言,这将非常昂贵。


为了获得最佳性能,您需要“覆盖索引”,而不是每个单独列上的(无用的)索引。至少,您需要 bs_photocomments 上的索引以 photoid 作为前导索引,后跟 id。包含active列将意味着可以“使用索引”满足内联 View 查询,而无需访问任何数据页。

... ON bs_photocomments (photoid, id, active)

有了这个索引,MySQL 应该能够相当有效地获得每个 photoid 的最大 id。同样,有一个索引

... ON bs_photocomments (id, comment, userid, dateposted, likephoto)

将意味着对 bs_photocomments 表 (c) 的外部查询也可以“使用索引”得到满足。 (MySQL 可能能够满足索引中的 ORDER BY,而不需要排序操作。(您需要检查 EXPLAIN 输出以查看 Extra 中是否出现“Using filesort”专栏。)

此外,这些覆盖索引可能会略微提高查询的性能。 (如果在不访问基础表中的页面的情况下从索引满足查询,则 EXPLAIN 输出将显示“使用索引”。)

  ON photos (photoid, path, smallfile, bigfile)

ON user (userid, username)

每个单独列上的大多数单独索引都是无用的;这些索引中的任何一个都不太可能被使用,因此它们所做的只是消耗资源。

关于Mysql查询Order By太慢,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14284535/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com