c# - 如何使用 asp.net 和 c# 流式传输 Excel 2007 或 Word 2007 文件

Question

我正在开发一个网络应用程序，需要流式传输各种文件。我可以处理 pdf、图像和旧版 Office 文档。但是，当我尝试处理 2007 文档时，它会中断。这是我的代码:

    Response.Buffer = true;
    Response.Clear();
    Response.ClearContent();
    Response.ClearHeaders();
    switch (FileExtension.ToLower())
    {
        case "pdf":
            Response.ContentType = "application/pdf";
            break;
        case "doc":
            Response.ContentType = "application/msword";
            break;
        case "docx":
            Response.ContentType = "application/vnd.ms-word.document.12";
            break;
        case "xls":
            Response.ContentType = "application/vnd.ms-excel";
            break;
        case "xlsx":
            Response.ContentType = "application/vnd.ms-excel.12";
            break;
        default:
            Response.ContentType = "image/jpeg";
            break;
    }
    Response.BinaryWrite(buffer);

我得到的错误是:

An invalid character was found in text content. Error processing resource 'http://DomainName/GetFile.aspx...PK

有什么建议吗？

Answer 1

根据简单的网络搜索，word和excel的正确mime类型是:

application/vnd.openxmlformats-officedocument.wordprocessingml.document
application/vnd.openxmlformats-officedocument.spreadsheetml.sheet

http://www.bram.us/2007/05/25/office-2007-mime-types-for-iis/

编辑:

以下简化示例适合我。它与您的不同之处在于它使用通用处理程序而不是 Web 表单(无论如何更适合这样的事情)。

要对其进行测试，请确保在应用程序的顶级文件夹中有一个名为 Book1.xlsx 的 excel 2007 文件。

DownloadSpreadsheet.ashx:

<%@ WebHandler Language="C#" Class="DownloadSpreadsheetHandler" %>

using System;
using System.Web;
using System.IO;

public class DownloadSpreadsheetHandler: IHttpHandler {

    public void ProcessRequest (HttpContext context) {
        context.Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
        string path = context.Server.MapPath("~/Book1.xlsx");
        using (FileStream spreadsheet = File.OpenRead(path))
        {
            CopyStream(spreadsheet, context.Response.OutputStream);
        }
    }

    public bool IsReusable {
        get {
            return false;
        }
    }

    private static void CopyStream(Stream input, Stream output)
    {
        byte[] buffer = new byte[32768];
        while (true)
        {
            int read = input.Read(buffer, 0, buffer.Length);
            if (read <= 0)
                return;
            output.Write(buffer, 0, read);
        }
    }

}