PHP 与 Phpmyadmin

Question

我得到了我在 phpmyadmin 上执行的代码，它 100% 有效

Create Temporary Table Searches  ( id int, dt datetime);
Create Temporary Table Searches1 ( id int, dt datetime, count int);

insert into Searches(id, dt) select a.id, now() from tblSavedSearches a;

insert into Searches1(id, dt, count)
select  
    b.savedSearchesId,
    (select c.dt from tblSavedSearchesDetails c where b.savedSearchesId = c.savedSearchesId order by c.dt desc limit 1) as 'dt', 
    count(b.savedSearchesId) as 'cnt'
from tblSavedSearchesDetails b
group by  b.savedSearchesId;

insert into tblSavedSearchResults(savedSearchId,DtSearched,isEnabled)
select id,now(),0 from Searches where not id in (select savedSearchId from tblSavedSearchResults);

update     tblSavedSearchResults
inner join Searches1 on tblSavedSearchResults.savedSearchId = Searches1.id    
Set        tblSavedSearchResults.DtSearched = Searches1.dt, tblSavedSearchResults.isEnabled = 1;

然而，当我在 php 中放入与下面相同的代码时，它会生成一个错误

$dba = DbConnect::CreateDbaInstance(); 
$query = "";

$query.="Create Temporary Table Searches  ( id int, dt datetime); ";
$query.="Create Temporary Table Searches1 ( id int, dt datetime, count int); ";

$query.="insert into Searches(id, dt) select a.id, now() from tblSavedSearches a; ";

$query.="insert into Searches1(id, dt, count) ";
$query.="select ";  
$query.="    b.savedSearchesId, ";
$query.="    (select c.dt from tblSavedSearchesDetails c where b.savedSearchesId = c.savedSearchesId order by c.dt desc limit 1) as 'dt', ";
$query.="    count(b.savedSearchesId) as 'cnt' ";
$query.="from tblSavedSearchesDetails b ";
$query.="group by  b.savedSearchesId; ";

$query.="insert into tblSavedSearchResults(savedSearchId,DtSearched,isEnabled) ";
$query.="select id,now(),0 from Searches where not id in (select savedSearchId from tblSavedSearchResults); ";

$query.="update     tblSavedSearchResults ";
$query.="inner join Searches1 on tblSavedSearchResults.savedSearchId = Searches1.id ";    
$query.="Set        tblSavedSearchResults.DtSearched = Searches1.dt, tblSavedSearchResults.isEnabled = 1; ";

$dba->DbQuery($query) or die(mysql_error());      

出现以下错误

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Create Temporary Table Searches1 ( id int, dt datetime, count int) insert into S' at line 1

如果有人可以帮助我...

谢谢

Answer 1

如果您的 $dba->DbQuery($query) 方法实际上使用了 mysql_query (我想它确实如此，因为您正在使用 mysql_error)，那么，您不能在每次调用时执行多个查询 (引用) :

mysql_query() sends a unique query (multiple queries are not supported) to the currently active database on the server that's associated with the specified link_identifier.

您必须:

• 分离您的查询，并为每个查询调用一次 mysql_query
  • 应该很简单，在这里:不要将所有查询连接到 $query 中，只需一个接一个地执行它们。
• 或者停止使用mysql_*，开始使用MySQLi ，它提供了一个 mysqli_multi_query功能