php - 在 PHP 中混合引号

Question

我有这个脚本可以从数据库中获取我的信息

$result = mysqli_query($con,"SELECT * FROM <table> WHERE id = 3");

while($row = mysqli_fetch_array($result))
  {
  echo '<p>'.$row['name'].'</p>' . " " .'<p>' . $row['description'] . '</p>' . " " . '<p>' . $row['price'] . '</p>';
  echo "<br>";
  echo '<img src="http://www.example.com/images/'.$row['profile_pic'].'" alt="profilepic" />';
  echo '<img src="http://www.example.com/images/'.$row['pic1'].'" alt="pic1" />';
      ^^^                                                *********
      Here is the problem because I should have sigle quote at the beginning and at the end, but I still have it above ***.And I use double quotes for the src on the <img> so those are taken too.
  echo '<img src="http://www.example.com/images/'.$row['pic2'].'" alt="pic2" />';
  echo '<img src="http://www.example.com/images/'.$row['pic3'].'" alt="pic3" />';
  }

如果我按照我的预期去做，我将需要另一组引述(可能是三重 :]])..我怎样才能以正确的方式做到这一点？

Answer 1

你的源代码看起来不错。您可以在单引号或双引号之前立即使用 \ 字符来转义，如下所示:

$variable = "my quote's are\"like this\"";

//输出:我的报价是“像这样”

同样:

$variable = '这是“我的引语”看起来不一样';

//输出:这是“我的引号”看起来不一样