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如果我的 Canvas 元素的 DataContext 中有以下四个属性
Point Center
double Radius
double StartAngle
double EndAngle
我可以在没有任何额外代码的情况下绘制弧线吗?
最佳答案
事实证明,提供自定义组件是最好的解决方案。我在我的代码中这样使用它
<Controls:Arc Center="{Binding Path=PreviousMousePositionPixels}"
Stroke="White"
StrokeDashArray="4 4"
SnapsToDevicePixels="True"
StartAngle="0"
EndAngle="{Binding Path=DeltaAngle}"
SmallAngle="True"
Radius="40" />
SmallAngle
当 true
时,将呈现点之间的小角度,而不考虑 StartAngle
和 EndAngle
的顺序。当 SmallAngle
为 false
时,弧逆时针呈现。
实现是
using System;
using System.Collections.Generic;
using System.Windows;
using System.Windows.Media;
using System.Windows.Shapes;
public sealed class Arc : Shape
{
public Point Center
{
get => (Point)GetValue(CenterProperty);
set => SetValue(CenterProperty, value);
}
// Using a DependencyProperty as the backing store for Center. This enables animation, styling, binding, etc...
public static readonly DependencyProperty CenterProperty =
DependencyProperty.Register(nameof(Center), typeof(Point), typeof(Arc),
new FrameworkPropertyMetadata(new Point(), FrameworkPropertyMetadataOptions.AffectsRender));
public double StartAngle
{
get => (double)GetValue(StartAngleProperty);
set => SetValue(StartAngleProperty, value);
}
// Using a DependencyProperty as the backing store for StartAngle. This enables animation, styling, binding, etc...
public static readonly DependencyProperty StartAngleProperty =
DependencyProperty.Register(nameof(StartAngle), typeof(double), typeof(Arc),
new FrameworkPropertyMetadata(0.0, FrameworkPropertyMetadataOptions.AffectsRender));
public double EndAngle
{
get => (double)GetValue(EndAngleProperty);
set => SetValue(EndAngleProperty, value);
}
// Using a DependencyProperty as the backing store for EndAngle. This enables animation, styling, binding, etc...
public static readonly DependencyProperty EndAngleProperty =
DependencyProperty.Register(nameof(EndAngle), typeof(double), typeof(Arc),
new FrameworkPropertyMetadata(Math.PI / 2.0, FrameworkPropertyMetadataOptions.AffectsRender));
public double Radius
{
get => (double)GetValue(RadiusProperty);
set => SetValue(RadiusProperty, value);
}
// Using a DependencyProperty as the backing store for Radius. This enables animation, styling, binding, etc...
public static readonly DependencyProperty RadiusProperty =
DependencyProperty.Register(nameof(Radius), typeof(double), typeof(Arc),
new FrameworkPropertyMetadata(10.0, FrameworkPropertyMetadataOptions.AffectsRender));
public bool SmallAngle
{
get => (bool)GetValue(SmallAngleProperty);
set => SetValue(SmallAngleProperty, value);
}
// Using a DependencyProperty as the backing store for SmallAngle. This enables animation, styling, binding, etc...
public static readonly DependencyProperty SmallAngleProperty =
DependencyProperty.Register(nameof(SmallAngle), typeof(bool), typeof(Arc),
new FrameworkPropertyMetadata(false, FrameworkPropertyMetadataOptions.AffectsRender));
static Arc() => DefaultStyleKeyProperty.OverrideMetadata(typeof(Arc), new FrameworkPropertyMetadata(typeof(Arc)));
protected override Geometry DefiningGeometry
{
get
{
double a0 = StartAngle < 0 ? StartAngle + 2 * Math.PI : StartAngle;
double a1 = EndAngle < 0 ? EndAngle + 2 * Math.PI : EndAngle;
if (a1 < a0)
a1 += Math.PI * 2;
SweepDirection d = SweepDirection.Counterclockwise;
bool large;
if (SmallAngle)
{
large = false;
d = (a1 - a0) > Math.PI ? SweepDirection.Counterclockwise : SweepDirection.Clockwise;
}
else
large = (Math.Abs(a1 - a0) < Math.PI);
Point p0 = Center + new Vector(Math.Cos(a0), Math.Sin(a0)) * Radius;
Point p1 = Center + new Vector(Math.Cos(a1), Math.Sin(a1)) * Radius;
List<PathSegment> segments = new List<PathSegment>
{
new ArcSegment(p1, new Size(Radius, Radius), 0.0, large, d, true)
};
List<PathFigure> figures = new List<PathFigure>
{
new PathFigure(p0, segments, true)
{
IsClosed = false
}
};
return new PathGeometry(figures, FillRule.EvenOdd, null);
}
}
}
关于c# - 如何用半径和起止角画圆弧,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16667072/
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