c# - 将异步回调传递给 Timer 构造函数

Question

我有异步回调，它被传递到 Timer(来自 System.Threading)构造函数:

private async Task HandleTimerCallback(object state)
{
    if (timer == null) return;

    if (asynTaskCallback != null)
    {
        await HandleAsyncTaskTimerCallback(state);
    }
    else
    {
        HandleSyncTimerCallback(state);
    }
}

和计时器:

timer = new Timer(async o => await HandleTimerCallback(o), state, CommonConstants.InfiniteTimespan,
            CommonConstants.InfiniteTimespan);

有没有办法在 lambda 中省略 o 参数？非异步的原因我可以将我的 handler 作为委托(delegate)传递

 timer = new Timer(HandleTimerCallback, state, CommonConstants.InfiniteTimespan,
            CommonConstants.InfiniteTimespan);

Answer 1

Is there any way to omit that o param in lambda?

当然，只需将您的事件处理程序方法定义为async void:

private async void HandleTimerCallback(object state)