mysql - 在 MySQL DBMS 中引发应用程序错误触发器

Question

我正在处理 MySQL 中的触发器，我想添加引发应用程序错误，但我的代码表明:

Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(-20000,'Pay is below Texas minimum wage!');

END IF;

END' at line 9

如果我删除引发应用程序错误的部分，它会完美地工作。

触发器:

DELIMITER @@
DROP TRIGGER IF EXISTS gmtt.after_update_mcorr @@

CREATE TRIGGER gmtt.after_update_mcorr
AFTER UPDATE ON gmtt.mcorr
FOR EACH ROW
BEGIN
       IF OLD.etat = '0' AND NEW.etat = '1' THEN
            INSERT INTO historique(message, User, dateHisto) VALUES (CONCAT( 'a achevé la Maintenance ', OLD.codeMaint) , CURRENT_USER(), NOW()); 
       ELSE
raise_application_error(-20000,'Pay is below Texas minimum wage!');     

    END IF;

    END @@ 
DELIMITER ;

Answer 1

您的语法似乎是 MySQL。然而，raise_application_error 是一个 Oracle 结构。您需要 signal，已记录 here :

DELIMITER @@
DROP TRIGGER IF EXISTS gmtt.after_update_mcorr @@
CREATE TRIGGER gmtt.after_update_mcorr
AFTER UPDATE ON gmtt.mcorr
FOR EACH ROW
BEGIN
   IF OLD.etat = '0' AND NEW.etat = '1' THEN
        INSERT INTO historique(message, User, dateHisto)
             VALUES (CONCAT( 'a achevé la Maintenance ', OLD.codeMaint) , CURRENT_USER(), NOW()); 
   ELSE
       signal sqlstate '-20000' set message_text = 'Pay is below Texas minimum wage!';     
   END IF;
END @@ 
DELIMITER ;