mysql - 天数累计

Question

我有一个如下所示的 MySQL 表:

date         count
2010-01-01   5
2010-01-02   6
2010-01-03   7

如何将每一天的总和累加到下一天？所以结果是这样的:

date         acum per day
2010-01-01   5
2010-01-02   11
2010-01-03   18

我想我需要某种 for(each date)... 但没有线索。

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这只是我在 Eric 的回答之后使用的最后一个查询。 (谢谢)。

从 SELECT t1.dia, sum(t2.operacions), sum(t2.amount)

(SELECT count(*) operations, sum(amount), date(b.timestamp) dia
    FROM transactions b group by date(b.timestamp)) t1 

INNER JOIN 

(SELECT count(*) operations, sum(amount), date(b.timestamp) dia
    FROM transactions b group by date(b.timestamp)) t2 

ON t2.dia <= t1.dia GROUP BY t1.dia

Answer 1

嗯，我认为这可行，但不确定性能如何:

SELECT t1.date, sum(t2.count)
FROM mytable t1 INNER JOIN mytable t2 ON t2.date <= t1.date
GROUP BY t1.date