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mysql - 每个派生表都必须在 MySQL 中有自己的别名错误

转载 作者:可可西里 更新时间:2023-11-01 07:17:07 24 4
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我有以下查询:

SELECT SUM( cost ) 
FROM (

SELECT s.cost
FROM sandwiches AS s
WHERE s.name = "Cheese Steak"
)
UNION (

SELECT p.cost
FROM pizza AS p
WHERE TYPE = "Plain"
AND SIZE = "L"
)

这给了我一个错误:

#1248 - Every derived table must have its own alias

最佳答案

你需要给你的临时表起别名

SELECT SUM( cost ) 
FROM
(
(
SELECT s.cost
FROM sandwiches AS s
WHERE s.name = "Cheese Steak"
) AS T1
UNION
(
SELECT p.cost
FROM pizza AS p
WHERE TYPE = "Plain"
AND SIZE = "L"
) AS T2
) AS T

关于mysql - 每个派生表都必须在 MySQL 中有自己的别名错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5824873/

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