MySQL: order by inside group by

Question

我有一个像这样的 mysql 表:

mysql> select * from pt_onhand where pn = '000A569011';
+------------+-----+----+--------+------------+---------+--------------+-----+
| pn         | pa  | mn | ACTIVE | locate     | onhand  | avg_cost     | whs |
+------------+-----+----+--------+------------+---------+--------------+-----+
| 000A569011 | P/A |    |        | AA-112     | 13.0000 | 0.0000000000|     |
| 000A569011 | P/A |    |        | PF120136.1 |  1.0000 | 5.4785156200 |     |
+------------+-----+----+--------+------------+---------+--------------+-----+

我想执行这样的查询:

mysql> select sum(onhand),max(locate),avg_cost from pt_onhand where pn = '000A569011' group by pn;
+-------------+-------------+--------------+
| sum(onhand) | max(locate) | avg_cost     |
+-------------+-------------+--------------+
|     14.0000 | PF120136.1  | 0.0000000000|
+-------------+-------------+--------------+

所以我的问题是:我能否在同一个查询中获取与 max(locate) PF120136.1 相关的 avg_cost 5.4785156200，怎么做？谢谢

Answer 1

有点乱，但应该可以解决问题:

select a.onhand, a.locate, p.avg_cost
from
    (select sum(onhand) onhand, max(locate) locate from pt_onhand where pn = '000A569011' group by pn) a
    join pt_onhand p on p.locate = a.locate