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mysql - 排名未正确确定

转载 作者:可可西里 更新时间:2023-11-01 07:05:29 25 4
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我正在使用这个查询:

SELECT A.place_idx,A.place_id,B.TOTAL_CNT,(@r := @r + 1) AS rank FROM CUSTOM_LIST
AS A
INNER JOIN
(SELECT @r := 0)
AS C
INNER JOIN
(SELECT place_id,COUNT(place_id) AS TOTAL_CNT from COUNT_TABLE GROUP BY place_id)
AS B ON B.place_id=A.place_id order by B.TOTAL_CNT desc;

结果如下:

1

但我想要这样的结果:

2

我需要如何修改我的查询?我做错了什么?

最佳答案

SELECT *,(@r := @r + 1) AS rank FROM 
(
SELECT A.place_idx,A.place_id,B.TOTAL_CNT FROM CUSTOM_LIST
AS A
INNER JOIN
(SELECT place_id,COUNT(place_id) AS TOTAL_CNT from COUNT_TABLE GROUP BY place_id)
AS B ON B.place_id=A.place_id order by B.TOTAL_CNT desc
) AS T, (SELECT @r := 0) AS tt

关于mysql - 排名未正确确定,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12409598/

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