mysql - 查找字符串中的数字位置

Question

下面是我在表 myTable

中的内容

+++++++++++++++
+ id + myWord +
+++++++++++++++
+  1 + AB123  +
+  2 + A413D  +
+  3 + X5231  +
+  4 + ABE921 +
+++++++++++++++

当我执行

SELECT id, Locate('1',myWord) as myPos
FROM myTable;

我的位置是 1。

+++++++++++++++
+ id + myPos  +
+++++++++++++++
+  1 + 3      +
+  2 + 3      +
+  3 + 5      +
+  4 + 6      +
+++++++++++++++

我想要实现的是找到整数的第一个位置，这样我就会得到下面的输出。

+++++++++++++++++++++++
+ id + myWord + myPos +
+++++++++++++++++++++++
+  1 + AB123  +  3    +
+  2 + A413D  +  2    +
+  3 + X5231  +  2    +
+  4 + ABE921 +  4    +
+++++++++++++++++++++++

知道如何实现吗？

Answer 1

在xdazz answer的帮助下，我做了一些修改，终于得到了答案......

SELECT 
  myWord, 
  LEAST (
    if (Locate('0',myWord) >0,Locate('0',myWord),999),
    if (Locate('1',myWord) >0,Locate('1',myWord),999),
    if (Locate('2',myWord) >0,Locate('2',myWord),999),
    if (Locate('3',myWord) >0,Locate('3',myWord),999),
    if (Locate('4',myWord) >0,Locate('4',myWord),999),
    if (Locate('5',myWord) >0,Locate('5',myWord),999),
    if (Locate('6',myWord) >0,Locate('6',myWord),999),
    if (Locate('7',myWord) >0,Locate('7',myWord),999),
    if (Locate('8',myWord) >0,Locate('8',myWord),999),
    if (Locate('9',myWord) >0,Locate('9',myWord),999)
  ) as myPos
FROM myTable;

Demo