php - 需要有关使用 PHP 在 mysql 数据库中插入逗号分隔数据的帮助

Question

数据库表中已有的演示数据:

INSERT INTO `csvtbl` (`ID`, `SKU`, `Product_Name`, `Model`, `Make`, `Year_From`, `Year_To`) VALUES
(1, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Galaxie', 'Ford', '1960', '1965'),
(2, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Thunderbird ', 'Fordtrest', '1960', '1965');

我使用下面的代码并在表中插入以逗号 (,) 分隔的年份:

INSERT INTO `diff_yearstbl` (`ID`, `SKU`, `Product_Name`, `Model`, `Make`, `Year`) VALUES
(1, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Galaxie', 'Ford', '1960,1961,1962,1963,1964,1965'),
(2, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Thunderbird ', 'Fordtrest', '1960,1961,1962,1963,1964,1965');

年份数据运行良好，但我想像年份一样插入数据 Make 和 Model，但这次只需插入以逗号 (,) 分隔的数据，如下例使用 SKU 字段。所以需要把上面两条记录合并成一行，如下图所示。

INSERT INTO `diff_yearstbl` (`ID`, `SKU`, `Product_Name`, `Model`, `Make`, `Year`) VALUES
(1, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Galaxie, Thunderbird', 'Ford, Fordtrest' '1960,1961,1962,1963,1964,1965');

下面是我所做的代码:

    $query = "select Year_TO - Year_From as diff_years, ID, SKU,Product_Name,Model,Make,Year_From,Year_To from csvtbl";
$result = mysql_query($query, $connect );

//$result = $db->query($select_test)->fetchAll();

if (count($result) > 0) 
{

    while($QryRow = mysql_fetch_assoc($result)) 
    {
        $diff_years = $QryRow['diff_years'];
        $Year_From = $QryRow['Year_From'];
        $SKU = $QryRow['SKU'];
        $Product_Name = $QryRow['Product_Name'];
        $Model = $QryRow['Model'];
        $Make = $QryRow['Make'];

        $years= array();
        for ($x = $QryRow['Year_From']; $x <= $QryRow['Year_To']; $x++) 
        {           
            $years[] = $x;    
        }

        $query_insert = "INSERT INTO diff_yearstbl(SKU,Product_Name,Model,Make,Year) VALUES('".$SKU."','".$Product_Name."','".$Model."','".$Make."','".implode('|',$years)."')";
        $s_insert = mysql_query($query_insert, $connect ); 
    }
} 
else 
{
    echo "<p>Nothing matched your query.</p>";
}

    ?>

请帮助一下。

Answer 1

在一条SQL语句中，应对长达100年:-

INSERT INTO diff_yearstbl(SKU, Product_Name, Model, Make, Year) 
SELECT   SKU,
        Product_Name,
        Model,
        Make,
        GROUP_CONCAT(Year_From + tens.acnt * 10 + units.acnt) AS ayear
FROM csvtbl
CROSS JOIN (SELECT 0 AS acnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) tens
CROSS JOIN (SELECT 0 AS acnt UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) units
WHERE (Year_From + tens.acnt * 10 + units.acnt AS ayear) <= Year_TO
GROUP BY SKU,
        Product_Name,
        Model,
        Make