mysql - 关于最大值的内连接表

Question

我正在尝试编写一个 MySQL 查询，从中提取卖家的信息和她最受欢迎的产品。这是由具有最多页面浏览量的产品决定的，即 MAX(page_views)。

虽然下面的查询只是随机抽取一个产品，而不是页面浏览量最多的产品。

"SELECT 
     seller.id, seller.language, seller.shop_name,seller.story, 
     seller.eng_story, product.id, product.image_thumb, product.title, 
     product.eng_title, product.price, MAX(product.page_views) 
  FROM seller 
     INNER JOIN product ON seller.id=product.seller_id 
  WHERE seller.handpicked='y' AND seller.shop_active='y' 
  GROUP BY seller.id 
  ORDER BY product.page_views
  LIMIT 0,5"

或者更准确地说，page_views 实际上是正确的数字，但我如何获得其他产品字段(id、图片、标题等)关于页面浏览量最多的产品。

表格数据:

卖家:

id | language | shop_Name | story     | eng_story   | handpicked | active
1  |   1      | mitienda  | hola mundo| Hello world | Y          | Y
2  |   1      | sisenor   | bonita    | beautiful   | N          | Y
3  |   2      | new_world | mi vida   | my life     | Y          | Y

产品:

id | seller_id | image_thumb | title    | eng_title | price | page Views
1  |  1        | /images/..  | sombrero | hat       | $5    | 10
2  |  1        | /images/..  | bufanda  | scarf     | $25   | 30
3  |  2        | /images/..  | arte     | art       | $15   | 15
4  |  3        | /images/..  | joyeria  | jewlery   | $10   | 1
5  |  2        | /images/..  | canasta  | basket    | $21   | 13
6  |  3        | /images/..  | ropa     | clothes   | $13   | 6

预期结果(浓缩):

seller.id | shop_name | product.id | pageviews | title    | price
  1       |  miteinda |     2      |    30     |  bufanda | $25
  3       |  newworld |     6      |     6     |  ropa    | $13

结果应该列出被挑选出来的卖家信息和他们最流行的页面浏览量的产品卖家按页面浏览量排序，总共限制为 5 个卖家。

Answer 1

SELECT  a.ID SellerID,
        a.Shop_Name,
        b.ID ProductID,
        b.pageViews,
        b.title,
        b.Price
FROM    seller a
        INNER JOIN Products b
            ON a.id = b.seller_ID
        INNER JOIN
        (
            SELECT  seller_ID, MAX(pageViews) max_view
            FROM    products
            GROUP   BY seller_ID
        ) c ON  b.seller_ID = c.seller_ID AND
                b.pageViews = c.max_View
WHERE   a.handpicked = 'Y' AND a.active = 'Y'

• SQLFiddle Demo

输出

╔══════════╦═══════════╦═══════════╦═══════════╦═════════╦═══════╗
║ SELLERID ║ SHOP_NAME ║ PRODUCTID ║ PAGEVIEWS ║  TITLE  ║ PRICE ║
╠══════════╬═══════════╬═══════════╬═══════════╬═════════╬═══════╣
║        1 ║ mitienda  ║         2 ║        30 ║ bufanda ║ $25   ║
║        3 ║ new_world ║         6 ║         6 ║ ropa    ║ $13   ║
╚══════════╩═══════════╩═══════════╩═══════════╩═════════╩═══════╝