mysql - SELECT 命令拒绝用户 'user' @'localhost' 表 'table'

Question

我已经在 MySQL 数据库服务器上部署了我的数据库。我有一个用户“bedgeaj_root@localhost”，它拥有所有权限。但它仍然给我错误:

SELECT command denied to user 'bedgeaj_root'@'localhost' for table 'transactions'

在网上搜索时，我了解到这是一些用户权限问题。但我不明白为什么会出现此错误，因为我已将所有权限授予该用户。

这是我的 cPanel 用户权限屏幕的屏幕截图:

这是我的堆栈跟踪:

   Caused by: net.sf.jasperreports.engine.JRException: Error executing SQL statement for : itemizedStatementReport_patientBalance
at net.sf.jasperreports.engine.query.JRJdbcQueryExecuter.createDatasource(JRJdbcQueryExecuter.java:246)
at net.sf.jasperreports.engine.fill.JRFillDataset.createQueryDatasource(JRFillDataset.java:1073)
at net.sf.jasperreports.engine.fill.JRFillDataset.initDatasource(JRFillDataset.java:667)
at net.sf.jasperreports.engine.fill.JRBaseFiller.setParameters(JRBaseFiller.java:1235)
at net.sf.jasperreports.engine.fill.JRBaseFiller.fill(JRBaseFiller.java:859)
at net.sf.jasperreports.engine.fill.JRBaseFiller.fill(JRBaseFiller.java:804)
at net.sf.jasperreports.engine.fill.JRFillSubreport.fillSubreport(JRFillSubreport.java:652)
at net.sf.jasperreports.engine.fill.JRSubreportRunnable.run(JRSubreportRunnable.java:59)
at net.sf.jasperreports.engine.fill.JRThreadSubreportRunner.run(JRThreadSubreportRunner.java:205)
... 1 more


   Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: SELECT command denied to user 'bedgeaj_root'@'localhost' for table 'transactions'
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27)
at java.lang.reflect.Constructor.newInstance(Constructor.java:513)
at com.mysql.jdbc.Util.handleNewInstance(Util.java:407)
at com.mysql.jdbc.Util.getInstance(Util.java:382)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1052)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3603)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3535)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1989)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2150)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2626)
at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2119)
at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:2281)
at net.sf.jasperreports.engine.query.JRJdbcQueryExecuter.createDatasource(JRJdbcQueryExecuter.java:239)
... 9 more

我正在使用这个查询:

    SELECT alias.patient_id , SUM(alias.balance) AS balance
    from (
    SELECT v.patient_id,trx.trx_id,trx.trx_status,trx.trx_seq,pb.billing_id,v.visit_id,v.visit_dt,forma t(SUM(tl.net_amount) - ifnull((SELECT SUM(pl.applied_amount+pl.discount_amount) FROM payment_lines pl where pl.trx_line_id = tl.trx_line_id),0.0),2)AS balance
    FROM ((transactions trx JOIN trx_lines tl ON (trx.trx_id = tl.trx_id))JOIN patient_billing pb ON(pb.billing_id = trx.billing_id))JOIN visits v ON (pb.visit_id = v.visit_id)
    where trx.trx_seq='4' AND trx.trx_status='PENDING' AND (date_format(v.visit_dt,'%Y/%m/%d')<date_format(DATE_SUB(NOW(), INTERVAL 1 day),'%Y/%m/%d'))
    group by tl.trx_id) alias
    where alias.patient_id = $P{patient_id}

按 alias.patient_id 分组]

我做错了什么？

Answer 1

grant all privileges on bedgeaj_medmax.transactions to 'bedgeaj_root'@'%'  identified by 'password';

试试这个。

编辑

Error: select command denied to user '<userid>'@'<ip-address>' for table '<table-name>'

请参阅上面链接中 pisces 的评论。