iphone - 在 iPhone sdk 中搜索数组中的值

Question

我有这样的数组:

(
  {
    id=1;
    Title="AAAA";
    period_id=1;
  },
  {
    id=2;
    Title="BBBB";
    period_id=2;
  },
  {
    id=3;
    Title="CCCC";
    period_id=2;
  },
  {
    id=4;
    Title="DDDD";
    period_id=2;
  },
  {
    id=5;
    Title="EEEE";
    period_id=3;
  },
)

问题:如何知道Period_id=2在数组中出现了多次？

帮我解决这个问题。

谢谢，

Answer 1

有很多方法可以做到这一点，其中一些在这里..

答:

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"period_id == %@", @"2"];
NSArray *newArray = [array filteredArrayUsingPredicate:predicate];
NSLog(@"%d", [newArray count]);

乙:

NSMutableArray *newArray = [[NSMutableArray alloc] init];
for (id obj in array)
{
    if([obj[@"period_id"] isEqualToString:@"2"]){
        [newArray addObject:obj];
    }
}
NSLog(@"%d", [newArray count]);

C:

NSArray *allIds = [array valueForKey:@"period_id"];
NSCountedSet *set = [[NSCountedSet alloc] initWithArray:allIds];
for (id item in set)
{
    NSLog(@"period_id=%@, Count=%d", item,[set countForObject:item]);
}

D:

NSArray *allIds = [array valueForKey:@"period_id"];
__block NSMutableArray *newArray = [[NSMutableArray alloc] init];
NSString *valueToCheck = @"2";
[allIds enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
   if([obj isEqualToString:valueToCheck])
       [newArray addObject:obj];
}];
NSLog(@"%d", [newArray count]);

E:

NSIndexSet *indexes = [array indexesOfObjectsPassingTest:^(id obj, NSUInteger idx, BOOL *stop) {
    return [[obj objectForKey:@"period_id"] isEqualToString:@"2"];
}];
NSArray *newArray = [array objectsAtIndexes:indexes];
NSLog(@"%d", [newArray count]);